9,090,900.0099 is the answer.
Answer:
The angle for G is 121°.
Step-by-step explanation:
Given that total angles in a triangle is 180° so in order to find the angle of G, first, you hav eto find the value of x :
x + (x - 5) + (3x + 25) = 180°
5x + 20° = 180°
5x = 160°
x = 32°
Next, you have to find the angle of G :
G = 3x + 25
G = 3(32) + 25
G = 96° + 25°
G = 121°
![\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$10000\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\to &1\\ t=years\to &12 \end{cases} \\\\\\ A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BCompound%20Interest%20Earned%20Amount%7D%0A%5C%5C%5C%5C%0AA%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%0A%5Cquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%20%26%5C%2410000%5C%5C%0Ar%3Drate%5Cto%204%5C%25%5Cto%20%5Cfrac%7B4%7D%7B100%7D%5Cto%20%260.04%5C%5C%0An%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%0A%5Ctextit%7Bannually%2C%20thus%20once%7D%0A%5Cend%7Barray%7D%5Cto%20%261%5C%5C%0At%3Dyears%5Cto%20%2612%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D10000%5Cleft%281%2B%5Cfrac%7B0.04%7D%7B1%7D%5Cright%29%5E%7B1%5Ccdot%2012%7D%5Cimplies%20A%3D1000%281.04%29%5E%7B12%7D%5C%5C%5C%5C%5C%5C%20A%5Capprox%2016010.32)
he then turns around and grabs that money and sticks it for another 9 years,
![\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} ~~ \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$16010.32\\ r=rate\to 5\%\to \frac{5}{100}\to &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semi-annually, thus twice} \end{array}\to &2\\ t=years\to &9 \end{cases} \\\\\\ A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18} \\\\\\ A\approx 24970.64](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BCompound%20Interest%20Earned%20Amount%7D%0A%5C%5C%5C%5C%0AA%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%0A~~%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%20%26%5C%2416010.32%5C%5C%0Ar%3Drate%5Cto%205%5C%25%5Cto%20%5Cfrac%7B5%7D%7B100%7D%5Cto%20%260.05%5C%5C%0An%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%0A%5Ctextit%7Bsemi-annually%2C%20thus%20twice%7D%0A%5Cend%7Barray%7D%5Cto%20%262%5C%5C%0At%3Dyears%5Cto%20%269%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D16010.32%5Cleft%281%2B%5Cfrac%7B0.05%7D%7B2%7D%5Cright%29%5E%7B2%5Ccdot%209%7D%5Cimplies%20A%3D16010.32%281.025%29%5E%7B18%7D%0A%5C%5C%5C%5C%5C%5C%0AA%5Capprox%2024970.64)
add both amounts, and that's how much is for the whole 21 years.
Remember, you can do ANYTHING to an equaiton as long as you do it to BOTH SIDES
we can try to get k by itself bymaking that -17 into 0 since k+0=k
-17+17=0 right so
K-17=-12
add 17 to BOTH SIDES
K+17-17=17-12
K+0=5
K=5
Since it is a square, the diagonals are congruent. If a square is split like this, it becomes two congruent right triangles. The relationship between the sides and hypotenuse is a 1:
![\sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20)
ratio. So if the diagonal of a square is 14 cm, then the side length would be 14/
![\sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20)
, which is approximately 9.899. I don't understand what the answer choices are, but you should be able to square root the numbers to determine the answer.