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natka813 [3]
1 year ago
8

A right cylinder and an oblique cylinder have the same radius and the same height. How do the volumes of the two

Mathematics
1 answer:
Novosadov [1.4K]1 year ago
7 0

Answer:

  A.  The volumes are the same, based on Cavalieri's principle.

Step-by-step explanation:

Cavalieri's principle tells us the volumes of solids will be identical if their cross sectional areas are identical at every height.

<h3>Application</h3>

A right cylinder and an oblique cylinder of the same height and radius will both have circular cross sections of the given radius at any height. Since the radius is the same, the area of the circle is the same. Hence the requirements of Cavalieri's principle are met, and the cylinders have the same volume.

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60 minutes is 20% of<br> minutes.
PilotLPTM [1.2K]

Answer:

60 minutes is 20% of 300 minutes

Step-by-step explanation:

let x be the number of total minutes

60 = 20% of x

20% = 1/5

60 = 1/5x

multiply both sides by 5

300 = x

x = 300 minutes

8 0
3 years ago
The length of a rectangle is 6 cm longer than its width.
oksian1 [2.3K]
2(6+w)+2(w)=40
12+2w+2w=40
12+4w=40
4w=28
w=7
Now we know that the width is 7; abd the length is 7+6 which is 13.
To find the area we multiply 13x7
The area is 92cm squared
4 0
2 years ago
81x-27=81x−27<br><br> what<br> is the answer
kykrilka [37]

The answer is all real numbers for x

because simplifying, you get both sides are equal

5 0
1 year ago
Read 2 more answers
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
2 years ago
Solve the for variable<br><br><br>c+7=13<br><br><br>c = ?
nika2105 [10]

Answer:

c=6

Step-by-step explanation:

c+7=13

-7        -7

c=13-7

c=6

7 0
3 years ago
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