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sladkih [1.3K]
2 years ago
5

If x = false and y = false, is the statement: not x or not y a) true b) false

Mathematics
1 answer:
pantera1 [17]2 years ago
6 0

Answer:

false

Step-by-step explanation:

X is equal to Y

therefore,

X = Y

X= false

Y = false

so,

false = false

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Bess [88]

Step-by-step explanation:

Is that the whole question or can you give me more information?

6 0
3 years ago
“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor
Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

C=2\pi r

<u><em>Find the radius of the sphere with a 5.50-meter circumference</em></u>

For C=5.50\ m

assume

\pi =3.14

substitute and solve for r

5.50=2(3.14)r

r=5.50/[2(3.14)]=0.88\ m

<u><em>Find the radius of the sphere with a 7.85-meter circumference</em></u>

For C=7.85\ m

assume

\pi =3.14

substitute and solve for r

7.85=2(3.14)r

r=7.85/[2(3.14)]=1.25\ m

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

SA=4\pi r^{2}

<u><em>Find the surface area of sphere with a 5.50-meter circumference</em></u>

For r=0.88\ m

assume

\pi =3.14

substitute

SA=4(3.14)(0.88)^{2}

SA=9.73\ m^{2}

<u><em>Find the surface area of sphere with a 7.85-meter circumference</em></u>

For r=1.25\ m

assume

\pi =3.14

substitute

SA=4(3.14)(1.25)^{2}

SA=19.63\ m^{2}

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

<u><em>Find the cost of sphere with a 5.50-meter circumference</em></u>

9.73*(92)=\$895.16

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

<u><em>Find the cost of sphere with a 7.85-meter circumference</em></u>

19.63*(92)=\$1,805.96

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0
3 years ago
Help me solve this problem pleaseeeeee
antiseptic1488 [7]

Answer:

y>6

Step-by-step explanation:

Simplify so 5y-2(y)-2(4)>10

3y-8>10

3y>18

y>6

7 0
3 years ago
What is this?<br> It is a alternate question
Eduardwww [97]

Answer:

complimentary angles

Step-by-step explanation:

6 0
3 years ago
27.) A customer went to a garden shop and bought some potting soil for $17.50 and 4 shrubs. The total bill was $53.50. Write and
Talja [164]

Answer:

c) The equation to find the price of each shrub is    $53.50 = 4 p + $17.50

The cost of 1 shrub = p =  $ 9.00

Step-by-step explanation:

The total number of shrubs purchased = 4

The price paid for potting soil = $17.50

The total bill of purchase = $53.50

Let us assume the cost of 1 shrub   = $p

The total amount spent of 4 shrubs = 4 x ( The price of each shrub)  =  4 p

TOTAL BILL = The amount paid for 4 shrubs +  AMOUNT paid for SOIL

⇒ $53.50 = 4 p + $17.50

Now. solving for p, we get:

53.50 - 17.50  = 4  p

or, 3 6  = 4 p

or, p = 36/4 = 9

or, p = 9

Hence, the cost of each shrub = $9

3 0
3 years ago
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