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Bingel [31]
4 years ago
14

Solve the equation 65=5+x

Mathematics
2 answers:
Elanso [62]4 years ago
4 0

Answer:

x = 60

Step-by-step explanation:

<u>Step 1:  Subtract 5 from both sides </u>

65 - 5 = 5 + x - 5

60 = x

Answer:  x = 60

scZoUnD [109]4 years ago
3 0

Answer:

60=x

Step-by-step explanation:

isolate x by subtracting 5 from both sides

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NEED TO KNOW ASAP<br> Which of the following is a quadratic inequality?<br> Oy&lt;2x+7<br> Oy Oy
Burka [1]

Answer:

  (c)  y < x^2 -5x

Step-by-step explanation:

A quadratic inequality is one that involves a quadratic polynomial.

<h3>Identification</h3>

The degree of a polynomial is the value of the largest exponent of the variable. When the degree of a polynomial is 2, we call it a <em>quadratic</em>.

For the following inequalities, the degree of the polynomial in x is shown:

  • y < 2x +7 . . . degree 1
  • y < x^3 +x^2 . . . degree 3
  • y < x^2 -5x . . . degree 2 (quadratic)

<h3>Application</h3>

We see that the degree of the polynomial in x is 2 in ...

   y < x^2 -5x

so that is the quadratic inequality you're looking for.

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<em>Additional comment</em>

When a term involves only one variable, its degree is the exponent of that variable: 5x^3 has degree 3. When a term involves more than one variable, the degree of the term is the sum of the exponents of the variables: 8x^4y3 has degree 4+3=7.

8 0
2 years ago
Please help me I am having a hard time with this activity
zysi [14]

Answer:

Step-by-step explanation:

b.

\frac{a^2+6a+9}{a^2-9} *\frac{3a-9}{a+3} \\=\frac{a^2+2*a*3+3^2}{a^2-3^2} *\frac{3(a-3)}{a+3} \\=\frac{(a+3)^2}{(a+3)(a-3)} *\frac{3(a-3)}{a+3} \\=\frac{3(a+3)^2}{(a+3)^2} \\=3

d.

\frac{3x^2-6x}{3x+1} *\frac{x+3x^2}{x^2-4x+4} \\=\frac{3x(x-2)}{3x+1} *\frac{x(1+3x)}{x^2-2x-2x+4} \\=\frac{3x(x-2)}{3x+1} *\frac{x(1+3x)}{x(x-2)-2(x-2)} \\=\frac{3x(x-2)}{3x+1} *\frac{x(1+3x)}{(x-2)(x-2) } \\=\frac{3x^2}{x-2)}

e.

\frac{2x^2-10x+12}{x^2-4} *\frac{2+x}{3-x} \\=\frac{2[x^2-5x+6]}{x^2-2^2} *\frac{2+x}{-(-3+x)} \\=\frac{2[x^2-2x-3x+6]}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2[x(x-2)-3(x-2)]}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2(x-2)(x-3)}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2}{-1} \\=-2

k.

\frac{6x^2-11x-10}{6x^2-5x-6} *\frac{6-4x}{25-20x+4x^2} \\=\frac{6x^2-15x+4x-10}{6x^2-9x+4x-6} *\frac{-4x+6}{4x^2-10x-10x+25} \\=\frac{3x(2x-5)+2(2x-5)}{3x(2x-3)+2(2x-3) } *\frac{-2(2x-3)}{2x(2x-5)-5(2x-5)} \\=\frac{(2x-5)(3x+2)}{(2x-3)(3x+2)} *\frac{-2(2x-3)}{(2x-5)(2x-5)} \\=\frac{-2}{2x-5}

7 0
3 years ago
Generate two equivalent fractions for 1/3
Vlad1618 [11]
If you have a fraction, you can multiply any constant, if you do it on both the top and bottom and get the same answer. For example, multiply 2 on both sides of 1/3 to get 2/6, or 3 times 1/3 to get 3/9. So 2/6 or 3/9 would work.
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3 years ago
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amid [387]

Answer:

(x+9)(3x+27)

Step-by-step explanation:

3x^2+54x+243 (243×3=729, Product=729, Sum=54) [27+27=54, 27×27=729]

3x^2+27x+27x+243

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3 years ago
I need help with this problem ​
Alecsey [184]
How do I get the answer

7 0
3 years ago
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