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Bingel [31]
4 years ago
14

Solve the equation 65=5+x

Mathematics
2 answers:
Elanso [62]4 years ago
4 0

Answer:

x = 60

Step-by-step explanation:

<u>Step 1:  Subtract 5 from both sides </u>

65 - 5 = 5 + x - 5

60 = x

Answer:  x = 60

scZoUnD [109]4 years ago
3 0

Answer:

60=x

Step-by-step explanation:

isolate x by subtracting 5 from both sides

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Aryan wants to plant a flower on the ground in the form of a rhombus. The diagonals of the rhombus measures 42 cm and 56 cm. Fin
Vlad1618 [11]

<u>Given</u><u> info</u><u>:</u><u>-</u>

Aryan wants to plant a flower on the ground in the form of a rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Find the perimeter of the field ?

<u>Explanation</u><u>:</u><u>-</u>

Given that

rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Let consider a rhombus ABCD

Let AC = (d1) = 42 cm

Let BD = (d2) = 56 cm

We know that

The digonals of a rhombus bisects each other at 90°.

AC = AO+OC

⇛ AC = 2 AO = 2 OC

⇛ AO = OC = AC/2

⇛ AO = OC = 42/2 = 21 cm

and

BD = BO+OD

⇛ BD = 2 BO = 2 OD

⇛ BO = OD = BD/2

⇛ BO = OD = 56/2 = 28 cm

We have,

∆AOB is a right angled triangle

By Pythagoras theorem,

AB² = AO²+OB²

⇛ AB² = 21²+28²

⇛ AB² = 441+784

⇛ AB² = 1225

⇛ AB = ±√1225

⇛ AB = ±35

AB is the length of the side which cannot be negative.

AB = 35 cm

We know that

All sides are equal in a rhombus

⇛ AB = BC = CD = DA

As we know

The Perimeter of a rhombus = 4×Side units

The perimeter of the rhombus ABCD

⇛ 4AB = 4BC = 4CD = 4DA

⇛ 4×35 cm

⇛ Perimeter = 140 cm

<em>∴</em><em> </em><em>T</em><em>he perimeter of the given field is 140 cm.</em>

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Step-by-step explanation:

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Answer:

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Blank 2: 0.18

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For blank 2, there are 9 single digit numbers, (1, 2, 3, 4, 5, 6, 7, 8, and 9) equaling 0.09. Multiply that by 2 and you get 0.18.

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