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Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
This is (x - 6)*x^1/2(x + 3)
= x^1/2 (x^2 - 3x - 18)
= x^(5/2) - 3x^(3/2) - 18x^(1/2)
This is an EXPONENT.
To do this all we need to do is multiply the base by itself how many times the power says.
(-6)² = (-6) × (-6) = 36
Recall that any negative number times another negative number is positive so that is why this would be positive.
So, (-6)² = 36
Hope I helped ya!!
It is 588.8 as all you have to do is subtract 0.210 from 589.01 and add up the ''.''
