Answer:
5 people will be left to play
<span>1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
One die can show the values 1-6, while the other die can only show 0 or 6. So the possible totals are 1 through 6 plus 0 and 1 through 6 plus 6. Written out, one-by-one, this gives:
1+0 = 1
2+0 = 2
3+0 = 3
4+0 = 4
5+0 = 5
6+0 = 6
1+6 = 7
2+6 = 8
3+6 = 9
4+6 = 10
5+6 = 11
6+6 = 12</span>
Answer:
is it from a textbook
Step-by-step explanation:
Answer:
1/9
Step-by-step explanation:
For these questions, you have to first find the probability of each event individually occuring then multiply these two probabilities together. So, lets first find the probability of Event 1 occuring (rolling a number higher than 1). On a dice, we know that there are 6 numbers (1, 2, 3, 4, 5, 6) of which the numbers 5 and 6 are higher than 4. Therefore, the proability of Event 1 occuring is 2/6 = 1/3. Now, we find the probability of event 2 occuring.
We know that there are 3 options on the spinner that the arrow can land on. It is also evident that they all have the same chance of landing on it. Therefore, the possibility is 1/3.
Now that we have both of our probabilities, we multiply the answer together.
Therefore, our answer will be:
1/3 x 1/3, which gives 1/9.
(7 1/2) / (3/4) =
(15/2) / (3/4) =
15/2 * 4/3 =
30/3 =
10 <== there will be 10 three-fourth ft pieces
