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2 years ago

How much does a $5.40 lunch cost if it is discounted by 10%

Mathematics

2 answers:

dedylja [7]2 years ago

7 0

Answer:

$4.86

Step-by-step explanation:

There are two approaches to this problem.

You can multiply the original value by 10% and subtract it from the original value. In this case, $5.40-(5.40×10%). This becomes $5.40-$0.54. This is $4.86.

You can simply multiply the original value by 90%. In this case, $5.40×90%. This also becomes $4.86.

notka56 [123]2 years ago

3 0

Answer:

$4.86

Step-by-step explanation:

Original price: $5.40

Discount: 10%

Discount amount:

10% of $5.40 = 0.1 × $5.40 = $0.54

Discounted price:

$5.40 - $0.54 = $4.86

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What is the measure of angle DOC, given that AB is congruent to DC

pickupchik [31]

Answer:

D. 65 degrees

Step-by-step explanation:

If two sides are congruent the corresponding angles are also congruent

5 0

3 years ago

Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -

rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

$y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\$

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by D and its formula is

$D=b^2-4ac\\$

Where

a= the coefficient of the $x^{2}$

b= the coefficient of $x$

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant and evaluate our answer accordingly .

Let us start with

$y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\$

Hence we have two real roots for this equation.

$y = 2x^2 - 6x + 5\\$

$y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D$

Hence we do not have any real root for this quadratic

$y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\$

Hence D>0 and thus we have two real roots for this equation.

$y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\$

Hence we have one real root to this quadratic equation.

7 0

3 years ago

( 18points)Help!!!

Mars2501 [29]

Answer:

It's indeed A. Yet I think of reporting multiple same questions as spam and nonsense titles.

but nah, I won't, would be kinda focused on the toxic part then :D

8 0

3 years ago

Please help me with 1,2 give me the answers and show me how you get it do not send me link please just write it right here pleas

Alex777 [14]

Pythagorean theorem is formula we would use:
1.)
c^2=a^2+b^2
c^2=10^2+24^2
c^2=100+576
c^2=676
c= √676
c=26 in

2.)
c^2=7^2+14^2
c^2=49+196
c^2=245
c= √245
c~15.65 cm

4 0

3 years ago

Y = -2x - 5

lions [1.4K]

Answer:

A. One line

Step-by-step explanation:

Let rearrange the system of equations into explicit forms:

$y = -2\cdot x - 5$