All categories

2 years ago

What is another way to name angle 3?

Mathematics

1 answer:

fiasKO [112]2 years ago

7 0

Answer:

intimately there are three types of angles a cute angle and angle between zero and 90° right angle and angle 90 degree angle of two angle and angle between 90 and 180 degree

You might be interested in

How to write 3.05 in word form

Arturiano [62]

Three and five hundredths

6 0

3 years ago

The sum of 6 and the product of 8 and x" into mathematical expression

Inga [223]

Answer:

6=8x

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

David created two functions. Function A can be represented by y=3/4x +2. Function be is represented by the graph below.

RideAnS [48]

Answer: don't know sorry

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value S₁ = 1.

• Assume the closed form is correct for all n up to n = k. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for n = k + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

3 years ago

Find x+y, if: 2x+3y=8 and 3x+5y=13

joja [24]

Answer is x = 1 & y = 2
the answer can be found using math-way

4 0

3 years ago