Explain what it means when elimintion results in an equation that is always true

Mathematics

1 answer:

iragen [17]3 years ago

8 0

If the answer is 0=0 then it has infinitely many solutions if the answer is 0=1 then it has no solution

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the probability of winning a game is 15% if you play 60 times how many times should you expect to win

mr Goodwill [35]

Answer:

1/60

15% of 60 = 9 9/60 x 8/60 = 72/120 8/60 x 7/60 = 56/120 6/60 x 5/60 = 30/120 4/60 x 3/60 =12/120 2/60 x 1/60=2/120.

Step-by-step explanation:

7 0

3 years ago

5x + 3 + x +4= 55. Solve for x. Please show your work. (This is Algebra, by the way.)

Kobotan [32]

Answer:

x=8

Step-by-step explanation:

We first simplify both sides of the equation so it turns out like this:

(5x+x) + (3+4) =55

6x+7=55

Then we subtract 7 from both sides:

6x+7-7=55-7

6x=48

From there we divide both sides by 6:

6x/6=48/6

x=8

8 0

3 years ago

Read 2 more answers

1.) Evaluate the indicated function, where f(x) = x2 − 8x + 3and g(x) = 7x − 5.

noname [10]

Answer:

1) (f + g) (5) = 18, 2) (f + g) (1/2) = - 13/4, 3) (f - g) (-1) = 14, 4) (f * g) (7) = 456, 5) (f/g) (- 2) = - 3/4, 6) (g ○ f)(x) = 6 x - 23, (f ○ g)(x) = 6 x - 6, 7) $(g \circ f) (x) = \frac{9}{x} - 24$ , $(f \circ g) (x) = \frac{1}{x - 2} + 5$ , 8) (f ○ g)(5) = 3

Step-by-step explanation:

1) $(f + g) (x) = x^{2}-8\cdot x + 3 + 7 \cdot x - 5\\(f + g) (x) = x^{2} - x - 2\\(f + g) (5) = 18$

2) $(f + g) (x) = x^{2} - 7 \cdot x + 4 + 6 \cdot x - 7\\(f + g) (x) = x^{2} - x - 3\\(f + g) (\frac{1}{2} ) = - \frac{13}{4}$

3) $(f - g) (x) = x^{2} - 3 \cdot x + 4 - 4 \cdot x + 2\\(f - g) (x) = x^{2} - 7 \cdot x + 6\\(f - g) (-1) = 14$

4) $(f \cdot g) (x) = (x^{2}-4\cdot x + 3) \cdot (3\cdot x - 2)\\(f \cdot g) (7) = 456$

5) $(f / g) (x) = \frac{x^{2}-3\cdot x + 2}{4 \cdot x - 8} \\(f / g) (-2) = - \frac{3}{4}$

6) $(g \circ f) (x) = 3 \cdot (2 \cdot x - 8) + 1\\(g \circ f) (x) = 6 \cdot x - 23\\(f \circ g) (x) = 2 \cdot (3 \cdot x + 1) - 8\\(f \circ g) (x) = 6 \cdot x - 6$

7) $(g \circ f) (x) = 3 \cdot (\frac{3}{x} - 6) - 6\\(g \circ f) (x) = \frac{9}{x} - 24\\(f \circ g) (x) = \frac{3}{3 \cdot x - 6} + 5\\(f \circ g) (x) = \frac{1}{x - 2} + 5$