If you read the inequality from center to left you get -2x - 8 < -44 then from center to the right it is -2x - 8 >= -8 you get D.
Answer is choice D.
The answer to your question is 15.6
There are 80 lights. 28 x 12 divided by 4 minus 4 lights for the 16 inches before the first light.
Answer:
A. g + (g + 14) = 82
Bonus: Gary trained 48 dogs. Triana trained 34.
Step-by-step explanation:
Since Gary trained 14 MORE dogs, anything with a minus sign is definitely wrong. As a result, B & C are eliminated. D is also eliminated because that simplifies to 2g + 28 = 82, which signifies Gary trained 28 more dogs, which is not true. That leaves A as our answer.
g + g + 14 = 82
<em>Combine g & g to get 2g.</em>
2g + 14 = 82
<em>Subtract 14 from both sides.</em>
2g = 82 - 14
2g = 68
<em>Divide both sides by 2.</em>
g = 68/2
g = 34
With that, we now know Triana trained 34 dogs. Add 14 to that, and you get 48 dogs, which is how many Gary trained.
Let the number of reserved tickets = x
Let the number of lawn seats = y
Constraint functions:
Maximum capacity means ![x+y\leq 20000](https://tex.z-dn.net/?f=x%2By%5Cleq%2020000)
For concert to be held ![x+y\geq 5000](https://tex.z-dn.net/?f=x%2By%5Cgeq%205000)
means ![y\leq x](https://tex.z-dn.net/?f=y%5Cleq%20x)
Objective functions :
Maximum profit equation p = 65x +40y
Intersection points :
(10000,10000) (20000,0)(2500,2500)(5000,0)
p at (10000,10000) = 65(10000) + 40(10000) = $1050000
p at (20000,0) = 65(20000) + 40(0) = $1300000
p at (2500,2500) = 65(2500) + 40(2500) = $262500
p at (5000,0) = 65(5000) + 40(0) = $325000
Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000
Please find attached the graph of it.