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xeze [42]
3 years ago
10

HELP !!!!!!MEEEEEEEEEEEE!!!!!!!!!!

Mathematics
2 answers:
yanalaym [24]3 years ago
8 0

Answer:

OB is the ray between OC and OA

Step-by-step explanation:

If my answer helped, kindly mark me as the brainliest!!

Thank You!

Nimfa-mama [501]3 years ago
7 0

Answer:

OA is right ay 40 degree

Step-by-step explanation:

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Does anyone know how to turn these into percents?? please help!!!!
crimeas [40]
In the picture find 15 and 20 the answer for 16) 3/2= 150%

8 0
3 years ago
If you apply the changes below to the absolute value parent function, f(x) = [xl,
Rus_ich [418]

Answer:

B:  g(x) = Ix - 4I + 6

Step-by-step explanation:

First, let's describe in a general way the transformations.

Vertical shift.

For a function f(x), a vertical shift of N units is written as:

g(x) = f(x) + N

If N is positive, the shift is upwards

If N is negative, the shift is downwards.

Horizontal shift.

For a function f(x), a horizontal shift of N units is written as:

g(x) = f(x + N)

If N is positive, the shift is to the left.

If N is negative, the shift is to the right.

Now we have the function:

f(x) = IxI

And we first have a shift of 4 units to the right, this is written as:

g(x) = f(x - 4)

Now we have a shift of 6 units up

This is written as:

g(x) = f(x - 4) + 6

Now, knowing that f(x) = IxI, we can write

g(x) = Ix - 4I + 6

Option B.

7 0
3 years ago
Simplify 2 + 3/5x - 1 - 1/5x​
balu736 [363]

Answer:

2/5x +1

Step-by-step explanation:

if you combine like terms you can check me to see if i'm right :) have a good day!

6 0
3 years ago
Read 2 more answers
Convert the following sum into a product. cosx + cos3x + cos5x + cos7x
kvv77 [185]

Answer:

4\cos x\cos (4x)\cos (2x)

Step-by-step explanation:

Given: cosx + cos3x + cos5x + cos7x

To convert: the given sum into product

Solution:

Use formula: \cos A+\cos B=2\cos \left ( \frac{A+B}{2} \right )\cos \left ( \frac{A-B}{2} \right )

cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos (2x)\cos (-x)+2\cos (6x)\cos (-x)\\=2\cos (2x)\cos (x)+2\cos (6x)\cos (x)\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]

cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]\\=2\cos x\left [2 \cos \left ( \frac{2x+6x}{2} \right )\cos \left ( \frac{2x-6x}{2} \right ) \right ]\\=2\cos x\left [ 2\cos (4x) \cos (-2x) \right ]\\=4\cos x\cos (4x)\cos (2x)

4 0
3 years ago
I need help pls due in like 5 min
Anni [7]

Answer:

input

Step-by-step explanation:

input is when you put something in to the function

7 0
3 years ago
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