The center-radius form<span> of the </span>circle<span> equation is in the format (x – h)</span>2<span> + (y – k)</span>2<span> = r</span>2<span>, with the center being at the point (h, k) and the radius being "r". Therefore, the center is located at point (1, -3) and is located in the fourth quadrant, last option. Hope this answers the question.</span>
Answer:
- y= -12
- x = 7
- q = -1
- x = 24
Step-by-step explanation:
1. ..............................................
- 6(y + 7) = 2(y - 3)
- 6y + 42 = 2y - 6
- 6y - 2y = -6 - 42
- 4y = -48
- y = -12
2...............................................
- 3x + 2(x - 5) = 25
- 3x + 2x - 10 = 25
- 5x = 25 + 10
- 5x = 35
- x = 7
3 . ..............................................
- 10q + 3q + 5 = 2(q - 3)
- 13q + 5 = 2q - 6
- 13q - 2q = -6 - 5
- 11q = -11
- q = -1
4. ..............................................
- 1/3(x + 6) = 2/3(x - 9)
- 3*1/3(x+6) = 3*2/3(x - 9)
- x + 6 = 2(x - 9)
- x + 6 = 2x - 18
- 2x - x = 6 + 18
- x = 24
Answer:
∠PTQ = 124°
Step-by-step explanation:
∠QPT = 90° - 62° = 28°
∠PQT = 28°
∠PTQ = 180° - 28° - 28° = 124°
Answer:
x = 11
Step-by-step explanation:
a straight line = 180 degrees . 180-125=55 . 55/5 = 11
Answer:
The answer is
8 x 24 x 4 x 56 x 37 x 85 = 135260160
