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2 years ago

What is the solution to the equation? 4√x-4 =3 A. -8 B. 16 C. 85 D. no solution

Mathematics

2 answers:

zhannawk [14.2K]2 years ago

6 0

Answer:

Step-by-step explanation:

4√(x-4) = 3

√(x-4) = 3/4

Square both sides:

x - 4 = 9/16

x = 4 + 9/16

x = 4 9/16.

kodGreya [7K]2 years ago

4 0

${\qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

$\qquad \sf \dashrightarrow \: \sqrt[4]{x - 4} = 3$

$\qquad \sf \dashrightarrow \: x - 4 = (3) {}^{4}$

$\qquad \sf \dashrightarrow \: x - 4 = 81$

$\qquad \sf \dashrightarrow \: x = 81 + 4$

$\qquad \sf \dashrightarrow \: x = 85$

So, the correct choice is 85

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3 years ago

A department store is having a sale in which every item is 38% off its original price. The regular price of a suit is $112. How

lara [203]

Answer: $42.56

Step-by-step explanation:

Percent discount in department store = 38%

The regular price of suit = $112.

Price taken off the regular price of the suit =

38% of $112

So, 38% of $112

= (38/100) x $112

= 0.38 x $112

= $42.56

(i.e the customer will pay $112 - $42.56 = $69.44 only for the suit)

Thus, the price taken off the regular price of the suit is $42.56

3 0

3 years ago

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Ivanshal [37]

Answer:

Step-by-step explanation:

6 0

3 years ago

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

3 years ago

2x^3 + 3x^2 -11x -6 divided by x - 2

Gnesinka [82]

p(x)= x-2

g(x)= 2x^3 + 3x^2 - 11x - 6

first we have to find the zero of the polynomial of x-2

p(x)= x-2 = 0

x=2

therefore,

p(x)= 2x^3 + 3x^2 - 11x - 6

p(2)= 2*2^3 + 3*2^2 - 11*2 - 6

= 2*8 + 3*4 - 11*2 - 6

= 16 + 12 - 22 - 6

= 28-28

= 0

Hope it helped u, ^_^.

3 0

3 years ago