56.52 ÷ pi(3.14) = 18
18 ÷ 2 =9
A = pi(3.14)r^2
A = 3.14 × 9^2
A = 3.14 × 81
A = 254.34in^2
Answer:
21 ft by 28 ft
Step-by-step explanation:
To maximize the area, see the attached.
Perimeter will be 4l+3w which is equal to the fencing perimeter, given as 168
4l+3w=168
Making l the subject then
4l=168-3w
l=42-¾w
Area of individual land will be lw and substituting l with l=42-¾w
Then
A=lw=(42-¾w)w=42w-¾w²
A=42w-¾w²
Getting the first derivative of the above with respect to w rhen
42-w6/4=0
w6/4=42
w=42*4/6=28
Since
l=42-¾w=42-¾(28)=21
Therefore, maximum dimensions are 21 for l and 28 for w
Answer:
C) 16, 6
Step-by-step explanation:
- Set AB and DC equal to eachother. 4x = x + 12.
- Subtract x from both sides. 3x = 12
- Divide by 3 to get x alone. x = 4
- Plug this x value in the equation for AB. 4•(4) = 16
- We know the AD equals 6, so that will be one of the values and we now know that AB equals 16.
The angle vertical to it is DF
57 + x + x + 130 = 167
57 + 2x + 130 = 167
187 + 2x = 167
- 187 - 187
---------------------------
2x = -20
------ -------
2 2
x = -10