Sorry me nobody else knew either lollll
Answer:
Option B, Barr graph
Explanation:
A bar graph is used for comparing several items all together based on any certain parameter.
Here, the lead content is the comparison parameter while the six sample of contaminated water wells acts as different items being compared.
A line graph is good to show a continous varying data set, while a circle graph is good to represent the component constitution of any major substance and a data table is best to represent a data set with multiple attributes.
Hence, option B is correct
Answer:
The possible blood types of their children are: type AB (iAiB), type A (iAi), type B (iBi), type O (ii)
Explanation:
Blood type in humans is controlled by a gene with multiple alleles. Alleles iA and iB are dominant over allele i but co-dominant. The following blood types are encoded by the following alleles:
Blood type AB - iAiB
Blood type A - iAiA or iAi
Blood type B - iBiB or iBi
Blood type O - ii
According to this question, a man who has type B blood has children with a woman who has type A blood. They are both heterozygous, meaning that the man's genotype is "iBi" while the woman's genotype is "iAi". Both parents will produce gametes as follows:
iBi = iB and i
iAi = iA and I
Using these gametes in a punnet square (see attached image), the following possible blood types are produced in the offsprings:
- type AB (iAiB)
- type A (iAi)
- type B (iBi)
- type O (ii)
Answer:
50%
Explanation:
Let's make a Punnett square to represent this, with X representing our dominant allele and x our recessive.
One homozygous dominant parent = XX
One heterozygous parent = Xx
X X
X XX XX
x Xx Xx
So two out of our four outcomes are heterozygous for the trait. That means the answer is <u>B. 50%.</u>