<span>If you have a quadratic equation in the form <span>a<span>x2</span>+bx+c</span>
</span>Step 1) Determine the product of AC (the coefficients in a quadratic equation)Step 2) Determine what factors of <span><span>a⋅c</span> sum to b</span>Step 3) "ungroup" the middle term to become the sum of the factors found in step 2Step 4) group the pairs.
RS => y - 5 = (8 - 5)/(1 - (-1)) (x - (-1))
y - 5 = 3/2 (x + 1) => slope = 3/2
ST => y - 8 = (-2 - 8)/(7 - 1) (x - 1)
y - 8 = -10/6 (x - 1) = -5/3 (x - 1) => slope = -5/3
TU => y - (-2) = (0 - (-2))/(2 - 7) (x - 7)
y + 2 = 2/5(x - 7) => slope = 2/5
UR => y = 5/(-1 - 2) (x - 2)
y = -5/3 (x - 2) => slope = -5/3
The median is the line joining the midpoints of the non-parallel sides.
Midpoint of RS = ((-1 + 1)/2, (5 + 8)/2) = (0, 13/2)
Midpoint of TU = ((7 + 2)/2, -2/2) = (9/2, -1)
Equation of the line joining (0, 13/2) and (9/2, -1) is given by y - 13/2 = (-1 - 13/2)/(9/2) x
y - 13/2 = (-15/2)/(9/2) x
y - 13/2 = -15/9x
18y - 117 = -30x
30x + 18y = 117
A) she incorrectly determined the GCF.
The GCF of 32ab - ab would be ab, not 8b.
Answer:
X =
Y = 204 =
Step-by-step explanation:
Answer:
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Step-by-step explanation:
