Hello from MrBillDoesMath!
Answer:
See Discussion section below for details
Root 1: -2, -1
Root 2: 0, 1
Root 3: 1, 2
Discussion:
From the attached plot, the the real zeroes are approximately
-1.8, .3, 1.5
-2 < -1.8 < -1
0 < 0.3 < 1
1 < 1.5 < 2
The consecutive integers are shown in bold face
Out of curiosity, it's now 11:38am PST. Did you write the question from a public school room, a school computer lab, or are you home tutored?
Thank you,
MrB
By taking a common factor, we will see that the equivalent expression is:
![12*\sqrt[3]{6c}](https://tex.z-dn.net/?f=12%2A%5Csqrt%5B3%5D%7B6c%7D)
<h3>
How to find the equivalent expression?</h3>
Here we start with the expression:
![5*\sqrt[3]{6c} + 7*\sqrt[3]{6c}](https://tex.z-dn.net/?f=5%2A%5Csqrt%5B3%5D%7B6c%7D%20%2B%207%2A%5Csqrt%5B3%5D%7B6c%7D)
Notice that if we define:
![\sqrt[3]{6c} = u](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B6c%7D%20%3D%20u)
We can rewrite our expression as:

Now we can take the common factor u to write:

Now if we replace u y the cubic root, we will get:
![12*\sqrt[3]{6c}](https://tex.z-dn.net/?f=12%2A%5Csqrt%5B3%5D%7B6c%7D)
So the correct option is the third one.
If you want to learn more about expressions:
brainly.com/question/2972832
#SPJ1
The formula for a falling object is
v = u +gt
where
u = initial velocity (=0 for a falling object)
g = acceleration due to gravity, 32.2 ft/s²
t = time, s
In terms of distance fallen,
v² = u² + 2gh
where h = distance fallen, ft.
Because h = 23 ft and u = 0, therefore
v² = 2*32.2*23 = 1481.2
v = 38.486 ft/s
Answer: 28.49 ft/s (nearest hundredth)
Answer:
it depends on your writing or typing speed and but illl go with 10
Step-by-step explanation:
Answer:
10 mph
Step-by-step explanation: