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Yanka [14]
2 years ago
5

How to solve these questions?(with work)

Mathematics
1 answer:
AveGali [126]2 years ago
3 0

The angles and length of the triangle area as follows:

  • ∠CBD = 61°
  • ∠A = 35°
  • AD = 32.77 units
  • BD = 22.94 units
  • BC = 11.12 units
  • CD = 9.73 units

<h3>How to find the sides and angle of a triangle?</h3>

The sum of angles in a triangle is 180 degree.

Therefore,

∠DBC = 180 - 29 - 90 = 61°

Hence,

∠A = 180 - 29 - 61 - 55 = 35°

∠CBD = 61°

Using trigonometric ratios,

sin 55 = opposite / hypotenuse

sin 55 = AD / 40

AD = 40 sin 55

AD = 32.7660817716

AD = 32.77 units

cos 55 = adjacent / hypotenuse

cos 55 = BD / 40

BD = 40 cos 55

BD = 22.943057454

BD = 22.94 units

sin 29 = 22.94 / BC

BC = 22.94 sin 29

BC = 11.1215326885

BC = 11.12 units

cos 29 = CD / 11.12

CD = 11.12 cos 29

CD = 9.72577114339

CD = 9.73 units

learn more on triangle here: brainly.com/question/17307037

#SPJ1

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Answer:

Simplifying

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Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-17' to each side of the equation.

17 + -17 + 8x = 137 + -17

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Divide each side by '8'.

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<u>39.28cm^2 </u>

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Answer:

Good morning.

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