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2 years ago

The maximum amount of air that can be expired after a maximum inspiration

1 answer:

5 0

The maximum amount of air that can be expired after a maximum inspiration is 4.5L lung volume. This is further explained below.

<h3>What are lungs?</h3>

Generally, The lung is one of a pair of organs located in the chest that is responsible for bringing oxygen into the body and expelling carbon dioxide from it.

In conclusion, 4.5 liters of lung capacity is the highest quantity of air that can be exhaled after having taken the maximum possible breadth.

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Mark and Jennifer, two conflict resolution mediators, met for coffee on Friday morning to make some plans for the weekend.

Arte-miy333 [17]

Answer:

it is facilitative mediation.

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3 years ago

Read 2 more answers

muscle contractions have _____ force at slower shortening velocities compared to higher shortening velocities.

Gnesinka [82]

Muscle contractions have increased force at slower shortening velocities compared to higher shortening velocities.

When you perform an activity, your muscles tighten, shorten, or lengthen as a result of the contraction. When you stretch or lift weights, hold anything in your hands, or pick something up, it may happen. Muscle relaxation, when contracted muscles return to their pre-contracted state, is frequently followed by muscle contraction.

The pace at which a muscle shortens during a contraction is known as the shortening velocity. With increased speed, a muscular contraction loses force. Myosin heads attach to actin and pull the actin inward, shortening the muscle.

To learn more about muscle contractions here: brainly.com/question/14907458

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1 year ago

I am writing with a complaint about the disrepair of River Creek Blvd. As a longtime resident of Bluff Point, I have noticed thi

pochemuha

The answer would be c

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3 years ago

Does attending an in-state public university help reduce the cost of college

LiRa [457]

yes becouse if its the state your from

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3 years ago

A baseball rolls in a straight line toward the catcher. This motion is shown on the following graph of horizontal position xxx v

Brrunno [24]

Based on the calculations, the average velocity of this ball is equal to 0.45 m/s.

<h3>How to calculate average velocity of this ball?</h3>

In order to calculate average velocity of this ball, we would determine the slope of the ball between the given time intervals:

$Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}$

Substituting the given parameters into the formula, we have;

Slope = 5.2/11.5

Slope = 0.45 m/s.

Therefore, the average velocity of this ball is equal to 0.45 m/s.

Read more on average velocity here: brainly.com/question/6504879

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Complete Question:

A baseball rolls in a straight line toward the catcher. This motion is shown on the following graph of horizontal position S vs. time t. What is the average velocity of the ball between the times t = 2 sec and t = 14 sec

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2 years ago