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1 year ago

Determine the standard form of the equation for the circle with center (h,k) =( -5, 1/2) and radius r=1

Mathematics

1 answer:

FrozenT [24]1 year ago

6 0

Answer:

$(x + 5) ^{2} + {(y - \frac{1}{2}) }^{2} = 1$

Step-by-step explanation:

the formula of a circle is

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

knowing the values of h, k, and r we can substitute them into the formula

knowing the

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The two figures are similar. Find the ratios (red to blue) of the perimeters and of the areas. Write the ratios as fractions in

vesna_86 [32]

Answer:

see explanation

Step-by-step explanation:

The perimeters of the similar figures have the same ratio as the sides.

ratio of perimeters = $\frac{11}{6}$

ratio of areas = 11² : 6² , that is 121 : 36

ratio of areas = $\frac{121}{36}$

3 0

2 years ago

What is the ratio for the volumes of two similar cylinders, given that the ratio of their heights and radii is 2:3?

ankoles [38]

Answer:

C IS YOUR ANSER.

Step-by-step explanation:

4 0

3 years ago

35% of f is 14. What is f? Enter your answer as a numeric expression.

Nata [24]

Answer:

Step-by-step explanation:

14/35 = f/100

35f = 14 x 100

f = 14 x 100 /35

f = 40

7 0

2 years ago

Read 2 more answers

What’s the quadrant

Vadim26 [7]

Hey there!!

Always remember this :

90-degree counterclockwise: (x, y) → (-y, x)

180-degree counterclockwise: (x, y) → (-x, -y)

270-degree counterclockwise: (x, y) → (y, -x)

1st quadrant : ( x , y )

second quadrant : ( -x , y )

Third quadrant : ( - x , - y )

Fourth quadrant : ( x , -y )

Now, the triangle abc lies in the 1st quadrant. So, all the vertexes will have positive values.

Let's take the vertex a as ( 1 , 2 )

Vertex b as ( 4 , 7 )

Vertex c as ( 5 , 9 )

If we rotate these values in 90 degress angle, these would become ( -y , x )

Vertex a : ( 1 , 2 ) ; After rotating : ( -2 , 1 )

Vertex b : ( 4 , 7 ) ; After rotating : ( -7 , 4 )

Vertex c : ( 5 , 9 ) ; After rotating : ( -9 , 5 )

Hope my answer helps!

3 0

2 years ago

brooke found the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form as follows

Goryan [66]

Answer:

The equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is $\mathbf{y=-4x-3}$

Step-by-step explanation:

Equation of line passing through the points (-7,25) and (-4,13) in slope-intercept form.

The general equation of slope-intercept form is: $y=mx+b$

First we need to find slope

The formula used for finding slope is: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We are given: $x_1=-7, y_1=25, x_2=-4, y_2=13$

Putting values in formula and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{13-25}{-4-(-7)}\\Slope=\frac{13-25}{-4+7}\\Slope=\frac{-12}{3}\\Slope=-4$

So, slope m= -4

Now finding y-intercept

Using slope m=-4 and point (-7,25) we can find y-intercept

$y=mx+b\\25=-4(-7)+b\\25=28+b\\b=25-28\\b=-3$

So, y-intercept b =-3

Now, the equation of required line having slope m=-4 and y-intercept b=-3 is:

$y=mx+b\\y=-4x-3$

So, the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is $\mathbf{y=-4x-3}$

3 0

2 years ago