Question

2

Answer 1

2(i).
(3y-20)+(4x-5)+(x+y-10)+(2x+5)=360 (Angles sum of it trapezium)
3y-20+4x-5+x+y-10+2x+5=360
7x+4y=390
(Shown)

2(ii).
(3y-20)+(2x+5)=180 (Interior Angles, Parallel Lines)
2x+3y=195
(Shown)

Hope it helps : )