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IgorLugansk [536]
3 years ago
6

What is the p(4,5) on two consecutive rolls of a number cube

Mathematics
2 answers:
dimaraw [331]3 years ago
8 0
The answer to this question would be (0,0)
Yanka [14]3 years ago
8 0

Answer:

p(4,5) = \frac{1}{36}

Step-by-step explanation:

The sample space for distribution of two consecutive throws of a dice is:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

There are total 36 observation.

Probability = \frac{\text{Number of favorable outcome}}{\text{Total number of observations}}

Thus, Probability(4,5) = \frac{1}{36}

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The path of a baseball, hit 3 feet above ground, is modeled by the function f(x)=-0.01x^2+x+3, where f(x) represents the vertica
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Answer:

Therefore the ball travel 102.92 feet horizontally before hitting the ground

Step-by-step explanation:

Given that, the path of a baseball, hit 3 feet above ground, is modeled by the function

f(x)=-0.01 x^2+x+3

where f(x) represents the vertical height of the ball in feet(Assume) and x is the horizontal distance in feet(Assume) .

When the ball hits the ground, then the vertically distance of the ball will be zero, i.e f(x)=0

\therefore -0.01 x^2+x+3=0

[Applying quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} , here a = -0.001, b=1 and c=3]

\Rightarrow x=\frac{-1\pm\sqrt{1^2-4.(-0.01).3}}{2.(-0.01)}

\Rightarrow x=-2.94, 102.92

Therefore the ball travel 102.92 feet horizontally before hitting the ground.

   

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