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EastWind [94]
2 years ago
12

Find a function f such that f '(x) = 5x3 and the line 40x + y = 0 is tangent to the graph of f.

Mathematics
1 answer:
Alex17521 [72]2 years ago
4 0

The function that is a  tangent to the graph of f is f(x) = (5/4)x^4+60

<h3>What is the concept of integral?</h3>

The definite integral can be interpreted as the resulting area of a region. In addition, it is a value in its result, that is, it does not depend on the variable x, which can be exchanged for any other variable without changing the value of the integral.

Knowing that :

  • 40x + y = 0 is tangent of f(x)
  • slope of the line = -40

therefore, f'(x)|x=a = -40, so only look for a we have:

5a^3 = -40\\a^3 = -8\\a = -2

if, x = -2, then y = 80 (since, 40x + y = 0), therefore, f(x) passes through (-2,80), so in the equation:

f'(x) = 5x^3\\f(x) = (5/4)x^4 + c\\80 = (5/4)(-2)^4 + c\\c = 60

Therefore,

f(x) = (5/4)x^4+60

See more about tangent at brainly.com/question/401236

#SPJ1

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Given collinear points E, F and G such that point F is the midpoint of segment EG. Find the new length of EG given that EF =5x+9
Veseljchak [2.6K]

Answer:

The length of EG is 58 units

Step-by-step explanation:

The midpoint of a segment divides it into two equal part

Let us use this rule to solve our question

∵ E, F, and G are collinear points

∵ Point F is the midpoint of segment EG

→ That means F divides EG into 2 equal segments EF and FG

∴ EF = FG

∵ EF = 5x + 9

∵ FG = 3x + 17

→ Equate them

∴ 5x + 9 = 3x + 17

→ Subtract 3x from both sides

∵ 5x - 3x + 9 = 3x - 3x + 17

∴ 2x + 9 = 17

→ Subtract 9 from both sides

∴ 2x + 9 - 9 = 17 - 9

∴ 2x = 8

→ Divide both sides by 2 to find x

∵ \frac{2x}{2}=\frac{8}{2}

∴ x = 4

→ Substitute x by 4 in EF and FG to find their lengths

∵ EF = 5(4) + 9 = 20 + 9 = 29

∵ FG = 3(4) + 17 = 12 = 17 = 29

∵ EG = EF + FG

∴ EG = 29 + 29 = 58

∴ The length of EG is 58 units

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