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RUDIKE [14]
3 years ago
6

16. Choose the wrong statement: a) Every natural number is a whole number. b) Every integer is a rational number. c) Every ratio

nal number is an integer. d) Every rational number is a real number.​
Mathematics
1 answer:
lakkis [162]3 years ago
8 0

Answer:

C

Step-by-step explanation:

YES

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Help me please due in 20 minutes
sashaice [31]

Answer:

D

Step-by-step explanation:

That is where the line meets.

6 0
3 years ago
Find f(x) - g(x) *
Studentka2010 [4]

Answer:

3x^3+13x^2-3x+7

Step-by-step explanation:

I dont know if your question is complete.

f(x) - g(x)

(4x^3+6x^2-3x+9)-(x^3-7x^2+2)\\4x^3+6x^2-3x+9-x^3+7x^2-2\\3x^3+13x^2-3x+7

6 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
How do you convert fraction to percent
devlian [24]

Answer: dividing

Step-by-step explanation:

8 0
3 years ago
Louisa used a gift card to pay for 3 meals
olasank [31]

Answer:

21

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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