Answer:
(B)
Step-by-step explanation:
Given a point on the line segment BD, the internal division formula is given by:
Therefore:
Therefore the fraction which compares BC to BD is
Answer:
By AA
ΔWXY ~ΔWVZ
Step-by-step explanation:
Here WXY is an isosceles triangle with legs WX & WY
So WX = WY
Hence ∠X = ∠Y
So ∠2= ∠3.
Now by angle sum property
∠1 + ∠2+∠3 = 180°
∠1+∠2+∠2=180°
2∠2 = 180° - ∠1 .......(1)
In triangle WVZ
WV = WZ
So ∠V = ∠Z
∠4 = ∠5
Once again by angle sum property
∠1 + ∠4 + ∠5=180°
∠1 + ∠4 + ∠4 = 180°
2∠4 = 180° - ∠1 ...(2)
From (1) & (2)
2∠2 = 2∠4
∠2=∠4
Now ∠W is common to both triangles
Hence by AA
ΔWXY ~ΔWVZ
A(n) = 9 + (n - 1) * 8
2nd term....n = 2
A2 = 9 + (2 - 1)*8
A2 = 9 + 1 * 8
A2 = 9 + 8
A2 = 17 <==
4th term...n = 4
A4 = 9 + (4 - 1) * 8
A4 = 9 + 3 * 8
A4 = 9 + 24
A4 = 33 <==
11th term...n = 11
A11 = 9 + (11 - 1) * 8
A11 = 9 + 10 * 8
A11 = 9 + 80
A11 = 89 <==
Answer:
16 to 35
Step-by-step explanation:
The width accounts for two sides of the fence, so we'll double it. 30 × 2 = 60
Now, to find minimum length subtract 60 from 92 and divide by 2 (for each side).
(92 - 60) ÷ 2 = 16
Do the same for the maximum length, but with 130.
(130 - 60) ÷ 2 = 35
This means the range for the length of the fence is between 16 and 35.