Who can solve this in 1 min 5678÷78

Mathematics

1 answer:

andreev551 [17]3 years ago

5 0

It is 72.7948718

~Hope that helped!~

~Izzy <3

You might be interested in

It is possible to measure the lensth

ollegr [7]

You cannot measure the length of a ray of a pair of rays but you can measure a line segment

5 0

3 years ago

HELPPP PLEASEEE<br> g(t) = 6 - 1<br> g<br> -) = -7

DedPeter [7]

t is -1

g ( t ) = 6t-1

g (-1) = 6(-1)-1

= -6-1 = -7

6 0

2 years ago

What is the fraction 70/75 equivalent to?

ki77a [65]

Answer:14/15

Step-by-step explanation:

7 0

3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$