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2 years ago

Find a12 given the geometric sequence 4, 8, 16, 32, ...

Mathematics

1 answer:

SSSSS [86.1K]2 years ago

6 0

The twelfth element of the geometric sequence is equal to 4,096. (Correct choice: D)

<h3>How to find a determined element of a geometric sequence by exponential formulae</h3>

Sequences are series of elements generated according to at least one condition, usually equations. geometric sequences are generated according to a exponential formulas, whose form and characteristics are described below:

f(n) = a · bⁿ ⁻ ¹ (1)

Where:

a - First element of geometric sequence
b - Common ratio of the geometric sequence
n - Element index within the geometric sequence

If we know that a = 4, b = 2 and n = 12, then the twelfth element of the geometric sequence from the statement is:

f(12) = 4 · 2¹² ⁻ ¹

f(12) = 4 · 2¹¹

f(12) = 4 · 2,048

f(12) = 4,096

The twelfth element of the geometric sequence is equal to 4,096. (Correct choice: D)

To learn more on geometric sequences: brainly.com/question/4617980

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At a local preschool, there is a ratio of three boys two every four girls. If there are 245 total preschoolers enrolled , Then h

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A ratio can be written in three different ways: 3 to 4, 3:4, and 3/4

What does this mean? It means that for every group of 7 students (3+4) there are 3 boys and 4 girls. And how many groups do we have? We have:

245/7= 35 We have 35 groups, and we just said that each group has 3 boys and 4 girls:

35*3= 105 boys

35*4= 140 girls

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3 years ago

X – 3y = 13 2x + 4y = -4 What is the solution?

MAVERICK [17]

X=4 Y=3 I hope this helped I don’t know if it is fully right

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4 years ago

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42 = -7 (z - 3) z = ?

liubo4ka [24]

Answer:

The answer to your question is z = -3

Step-by-step explanation:

Expand 42 = -7(z - 3)

42 = -7z + 21

Simplify 7z = -42 + 21

7z = -21

Clear z z = $\frac{-21}{7}$

z = -3

3 0

3 years ago

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Ava wants to draw a parallelogram on the coordinate plane. She

wolverine [178]

Answer:

$k =(2,1)$

$JK = 2$

Step-by-step explanation:

Given

$J = (0,1)$ ---- $(x_1,y_1)$

$H = (1,-2)$ --- $(x_2,y_2)$

$I = (3,-2)$ --- $(x_3,y_3)$

See attachment for grid

Solving (a): The coordinates of K

The parallelogram has the following diagonals: IJ and HK

Diagonals bisect one another. So:

Midpoint of IJ = Midpoint of HK

This gives:

$\frac{1}{2}(I + J) = \frac{1}{2}(H+K)$

$\frac{1}{2}(x_3+x_1,y_3+y_1) = \frac{1}{2}(x_2+x,y_2+y)$

$\frac{1}{2}(3+0,-2+1) = \frac{1}{2}(1+x,-2+y)$

$\frac{1}{2}(3,-1) = \frac{1}{2}(1+x,-2+y)$

Multiply through by 2

$(3,-1) = (1+x,-2+y)$

By comparison:

$1 + x = 3$

$-2 + y = -1$

Solve for x and y

$x = 3 - 1 =2$

$y = -1 +2 = 1$

So, the coordinates of k is:

$k =(2,1)$

The length of JK is calculated using distance (d) formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

$J = (0,1)$ ---- $(x_1,y_1)$

$k =(2,1)$ ---- $(x_2,y_2)$

So:

$d = \sqrt{(0 - 2)^2 + (1 - 1)^2$

$d = \sqrt{(- 2)^2 + (0)^2$

$d = \sqrt{4 + 0$

$d = \sqrt{4$

$d = 2$

Hence:

$JK = 2$

8 0

3 years ago

You want to buy a new sports car from roy's cars for $51,800. the contract is in the form of a 48-month annuity due at an apr of

qwelly [4]

The present value of an annuity is given by

$PV= P\left(\frac{1-\left(1+ \frac{r}{t}\right)^{-nt} }{ \frac{r}{t} } \right)$

where: PV is the current value of the annuity, P is the periodic payment, r is the apr, t is the number of compounding in one year and n is the number of years.

Thus, given that PV = $51,800; r = 7.8% = 0.078; t = 12; n = 4.

$51,800= P\left(\frac{1-\left(1+ \frac{0.078}{12}\right)^{-4\times12} }{ \frac{0.078}{12} } \right) \\ \\ =P\left(\frac{1-(1+ 0.0065)^{-48} }{ 0.0065 } \right)=P\left(\frac{1-(1.0065)^{-48} }{ 0.0065 } \right) \\ \\ =P\left(\frac{1-0.7327}{ 0.0065 } \right)=P\left(\frac{0.2673}{ 0.0065 } \right)=41.12P \\ \\ \Rightarrow P= \frac{51,800}{41.12} =\$1,259.73$

Therefore, the monthly payment is $1,259.73

6 0

4 years ago

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