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Question

3 years ago

9

and $50^{99}$ .

Hint: Identity $(a+b)(a-b)=a^2-b^2$ .

1 answer:

Greeley [361] · Answer 1 · 2023-02-23T16:31:28+03:00

50^99 is greater than 99!

<h3>How to compare the numbers?</h3>

The numbers are given as:

99! and 50^99

When the above numbers are estimated using a calculator, we have:

99! = 9.332622e+155

50^99 = 1.577722e+168

Next, we compare the exponents

168 and 155

168 is greater than 155

Hence, 50^99 is greater than 99!

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