Beautiful ! What a great exercise ! I won't even check to verify
that 1:10⁻¹⁹ is an appropriate scale to map the Milky Way onto a
football field. I'll just accept it and go from there.
(4.4 light years) x (10⁻¹⁹) = (2.5848 x 10¹³ miles) x (10⁻¹⁹)
= 2.5848 x 10⁻⁶ mile
= 0.164 inch .
(1,391,400 kilometers) x (10⁻¹⁹) = 1.3914 x 10⁻¹⁰ meter
Research Conclusions:
If the Milky Way shrinks to fit on a football field, then
-- Alpha Centauri is 0.164 inch from us.
-- The sun's diameter is about 1.39 times that of a Hydrogen atom.
Playing with this same fun concept a little more:
-- The Earth is sailing around in its orbit, once a year,
about 0.000015 millimeter from the sun.
-- It takes light almost 27 years to travel 1 inch !
wow !
Answer:
-9y-2(2-7y)+4 expand the brackets using-2
Step-by-step explanation:
-9y-4+14y+4
arrange the like terms
-9y+14y-4+4
=5y becoz -4+4=0
ans=5y
Answer:
The total number of apples is 17
Step-by-step explanation:
(a)
Number of green apples = 4
P ( that all three apples are green)
= (limit 4 and 3) / (limit 17 and 3)
= 4! / 3!(4−3)!
= 17! / 3!(17−3)!
= 1 / 170
= 0.005
(b)
Number of red apples = 8
P(that all three apple are green)
=(limit 8 and 3) / (limit 17 and 3)
= 8! / 3!(8−3)!
= 17! / 3!(17−3)!
= 7 / 85
= 0.082
Now,
P(that no three apple is red)= 1−0.082 = 0.918
c)
P(of selecting 4 apple that contain at least 2 red apples)
= (limit 8 and 2) /( limit 17 and 2) X (2/15) + (limit 8 and 3) /(limit 17 / 3) X (1/14)
= (7/34) × (2/15) + (7/85) × (1/14)
= 0.027 + 0.058
= 0.085
d)
P(that the second apple selected is yellow given that the first apple is red)
= (limit 5 and 1) / ( limit 16 and 1)
= 5! / 1!(5−1)!
= 16! / 1!(16−1)!
= 5 /16
= 0.3125
We know that
[area of the painting]=13 in* 17 in-----> 221 in²
if a<span>n artist painting at
$0.30 per --------------> 1 in</span>²
x$--------------> 221 in²
X=221*0.30------> x=$66.30
the answer is
$66.30
24 / 8 = 3
she eats 1 every 3 minutes
so
33 / 3 = 11
ur right.
