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scZoUnD [109]
2 years ago
12

For the week , emma had originally selected 8 intervals the interval she put up was not picked up or swapped , nor did she show

up to service it her technical issue had also prevented her from servicing 45 minutes emma was also 5 mins late for two other intervals what was emma resulting ca percentage for the week
Mathematics
1 answer:
NNADVOKAT [17]2 years ago
8 0

Option(C): 85%.

Considering the above info given on Emma's activity, she was also late by 5 minutes for two others intervals. And her technical issue was preventing her from servicing for 45 minutes.

ICAI recently announced the results of the CA final exams for the May session. A total of 6,657 candidates appeared for group I and 63,253 candidates appeared for Group II out of which 14,643 and 13,877 candidates cleared the exam, respectively. The pass percentage recorded for the May session was only around 21 percent.

ca passing % will always stay low as it's a prestigious degree to get. it's a symbol of sheer hard work and dedication. however these days it is an all-time low if u will compare the results of the last 10 attempts. it is because market demand for ca's has gone very low.

Learn more about percentages at

brainly.com/question/843074

#SPJ4

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What is the minimum number of angles required to determine the Cartesian components of a 3D vector and why?
Reika [66]

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Now, a vector P lies in all of them.

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4 0
3 years ago
A mistake was made in mixing the lemonade—<br> PLEASE HELP!!
beks73 [17]

Answer:

Part A:

4 + x = y

0.5*4 + 1*x = 0.7*y

x = 8/3\ quarts\ of\ 100\%\ solution

y = 20/3\ quarts\ of\ 70\%\ solution

Part B:

x + y = 10

2x + 3y = 23

x = 7 and y = 3

Step-by-step explanation:

Part A:

The inicial concentration of the lemonade is 50%, and the volume is 4 quarts, and we will add x quarts of a lemonade with a concentration of 100%, so the total volume will be y, and the concentration will be 0.7, so we have that:

4 + x = y

0.5*4 + 1*x = 0.7*y

Using the value of y from the first equation in the second one, we have:

2 + x = 0.7*(4 + x)

2 + x = 2.8 + 0.7x

0.3x = 0.8

x = 8/3\ quarts

y = 4 + 8/3 = 20/3\ quarts

Part B:

If he shoots a total of ten targets, we can write the equation:

x + y = 10

Each stationary target is 2 points, and each moving target is 3 points, so if the total points is 23, we have:

2x + 3y = 23

If we subtract the second equation by two times the first one, we have:

2x + 3y - 2*(x + y) = 23 - 2*10

2x + 3y - 2x - 2y = 23 - 20

y = 3

x + 3 = 10 ⇒ x = 7

4 0
3 years ago
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