That's geometric sequence
T7 = T5*r^2 = T5+1920
r = 2, so
4*T5 = T5 + 1920
3T5 = 1920
T5 = 640
640 = 2^4 * 40
So, a=40 and the sequence is
40 80 160 320 640 1280 2560 5120 10240 20480 40960 ...
Note that 2560 = 640 + 1920
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At x-intercept, y value = 0,
For t(x), x = 1 when y = 0, i.e. x-intercept = 1
for 3x - 2y + 6 = 0, when y = 0,
3x - 2(0) + 6 = 0
3x + 6 = 0
3x = -6
x = -6/3 = -2
i.e. x-intercept = -2
Therefore, t(x) has the highest x-intercept of 1.
Given:
3x + 5 = -28 - 10
Let's find x.
3x + 5 = -28 - 10
3x + 5 = -38
Subtract 5 from both sides:
3z
Answer:
D) 57
Step-by-step explanation:
1/3x- 1/2 = 18 1/2
1/3x = 19
(3) * 1/3x = 19 (3)
x = 57