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2 years ago

13

A six sided fair die is rolled with two coins, all sides of a fair die have equal chances of being displayed ,Find the probabili

ty of no heads.

1 answer:

Marta_Voda [28]2 years ago

7 0

6% is the correct answer

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I tried to scream but my head was under water.....

sukhopar [10]

They called me weak

Like I'm not just somebody's daughter

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3 years ago

aisha and brendan are watching a hot air balloon. the angle of elevation for aisha is 65 degrees. what is the angle of elevation

astra-53 [7]

Using the law of sins:

B =sin^−1((sin(A)⋅a)/b) = sin^−1((sin(65)⋅110)/155)=40.03 degrees

B= 40.03 degrees (round as needed)

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4 years ago

Every 3 days, Marco fills up his car with gas. Every 8 days, he washes his car. On what day will Marco fill his car with gas and

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3 years ago

Read 2 more answers

A circle has radius 50 cm. Which of these is closest to its area?

olga55 [171]

Answer:

7854 cm²

Step-by-step explanation:

3.14 x 50² = 7850

4 0

3 years ago

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0

3 years ago