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lubasha [3.4K]
3 years ago
5

Please help me!! I'm terrible at math

Mathematics
1 answer:
Archy [21]3 years ago
5 0
Girl thats so easy i can help you 

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G=[(4,-6), (-9.0), (-9,-4), (-8,4)] what is the domain and range of G?
s2008m [1.1K]
Hey there!
The domain and range for G are as follows:
Domain: -9, -9, -8, 4
Range: -6, -4, 0, 4
Hope this answer helps you out!
4 0
3 years ago
36.75 divided by 7.5
Tomtit [17]

I attached a photo of the work.

If you have any further questions feel free to ask.

Hope this helps

6 0
3 years ago
I will mark brainliest.
Vlad1618 [11]

9514 1404 393

Explanation:

sum -- the result of addition: 5x+1

term -- a constant, variable, or product of a constant and one or more variables. In the more general sense, a term is any part of the expression that can be considered by itself. An example is 5x

product -- the result of multiplication: 9(5x+1), where 9 is multiplied by the sum (5x+1)

factor -- part of a product: x

quotient -- the result of division: 9(5x+1)÷3

coefficient -- a constant, or the constant that multiplies the variables in a term: 5

_____

<em>Additional comment</em>

The way this is written, there will be the tendency to think of 3y as a term in the same sense that 5x is a term. That would be incorrect. The Order of Operations has you interpret this expression as ...

  \dfrac{9(5x+1)}{3}\cdot y

8 0
3 years ago
Factor each experssion. 8x+16y
Neko [114]
8x + 16y = \boxed{\bf{8(x + 2y)}}
7 0
3 years ago
A circle is centered at the point (-3, 2) and passes through the point (1, 5) what is the radius of the circle
fomenos

Answer:

5 units

Step-by-step explanation:

Center of the circle = (-3, 2)

Point on the circle = (1, 5)

Radius of the circle will be equal to the distance between the points (-3, 2) & (1, 5)

\therefore \: radius \: of \: the \: circle \\  =  \sqrt{ {( - 3 - 1)}^{2} +  {(2 - 5)}^{2}  }  \\  =  \sqrt{ {( - 4)}^{2}  +  {( - 3)}^{2} }  \\  =  \sqrt{16 + 9}  \\  =  \sqrt{25}  \\  \therefore \: radius \: of \: the \: circle  = 5 \: units

6 0
3 years ago
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