Class A
14 - 4 = 10
Class B
16 - 12 = 4
answer
Class A has greater <span>interquartile range</span>
Answer:
<em>The slowest train goes at 86 mph and the fastest train goes at 96 mph.</em>
Step-by-step explanation:
<u>Distance and Speed</u>
Assume x is the speed of the slowest train, therefore the speed of the fastest train is x+10.
The distance is calculated as:
d = vt
Where v is the speed and t is the time.
The distance traveled by each train in 5 hours is:
Slowest: 5x
Fastest: 5(x+10)
The sum of both distances is 910 miles:
5x + 5(x + 10) = 910
Operating:
5x + 5x + 50 = 910
10x = 910 - 50 = 860
x = 860/10
x = 86
The slowest train goes at 86 mph and the fastest train goes at 96 mph.
Answer:
Step-by-step explanation:
x²+5x-84
look for the factors of 84 that when you add together it will give +5
look for the factors of 84 that when you multiply together it will give -84
12 and 7
addition, multiplication
-12+7 = -5 -84
-12-7= -19 84
+12-7 = +5 -84 correct
then equate into the =5x and -84
x²+12x-7x-84
then factorize
x(x+12)-7(x+12)
(x-7)(x+12)
Answer:
196 minutes
Step-by-step explanation:]
2x10 is 20 and if you divide 5/10 its 2 so the 4 in 4/5 is the total of 8 because 10 would mean 5/5 and 20+8=28 so 28x7 is 196
