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2 years ago

Pls help I’ll mark u brain

Mathematics

1 answer:

Fofino [41]2 years ago

6 0

Answer:

A: y=6x

B: A

Step-by-step explanation:

A: Rise over run

B: You can use the points to determine the answer, 6(2)=12 (2,12) 6(3)=18 (3,18)

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Try to fill in the missing numbers

GrogVix [38]

9514 1404 393

Answer:

[[274][895][136]]

Step-by-step explanation:

Starting with the middle row, we need a product of two single-digit numbers that is between 53-1 = 52 and 53-9 = 44. Possible products are 5×9=45 and 6×8=48. This means the number in the middle position in the left column must be 8 or 5.

The middle number in the left column cannot be 5, because we must be able to get -5 by subtracting that number from a sum that is at least 3 = 1+2. So, the middle number in the left column is 8, the other two numbers in that column are 1 and 2, and the other two numbers in the middle row are 5 and 9.

There is no product of single-digit numbers that is 30-1 = 29, so the upper left number must be 2, and the bottom left number must be 1. The other two numbers on the top row must be 4 and 7, so that row's equation is 2+4×7=30.

The only remaining digits are 3 and 6. In order to have -3 on the bottom row, the equation there must be 1×3-6 = -3. Then the middle digit must be divisible by 3, so must be 9.

Our solution is ...

row 1: 2 + 7 × 4 = 30

row 2: 8 + 9 × 5 = 53

row 3: 1 × 3 - 6 = -3

And that makes the column equations be ...

col 1: 2 - 8 + 1 = -5

col 2: 7 + 9 / 3 = 10

col 3: 4 × 5 - 6 = 14

6 0

3 years ago

Please help fassssst

Zarrin [17]

Answer:

$\dfrac{9}{2}$

Step-by-step explanation:

You can do this using the quadratic equation:

$x =\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

Let's first setup our expression:

4x² + 12x = 135

the quadratic formula is:

ax² + bx + c = 0

4x² + 12x - 135 = 0

Then:

a = 4

b = 12

c = -135

Now we plug in our coefficients and solve:

$x =\dfrac{-12\pm\sqrt{12^{2}-4(4)(-135)}}{2(4)}$

We solve for both to determine the positive one:

$x =\dfrac{-12+ \sqrt{12^{2}-4(4)(-135)}}{2(4)}$ $x =\dfrac{-12- \sqrt{12^{2}-4(4)(-135)}}{2(4)}$

$x =\dfrac{-12+ \sqrt{144+2160}}{8}$ $x =\dfrac{-12- \sqrt{144+2160}}{8}$

$x =\dfrac{-12+ \sqrt{2304}}{8}$ $x =\dfrac{-12- \sqrt{2304}}{8}$

$x =\dfrac{-12+ 48}{8}$ $x =\dfrac{-12- 48}{8}$

$x =\dfrac{36}{8} = \dfrac{9}{2}$ $x =\dfrac{-60}{8} = \dfrac{-15}{2}$

So if you are looking for a positive solution, just take the positive one as x.

8 0

3 years ago

(40x9)÷(4x8)=x solve for variable of x

nikklg [1K]

The answer is: " x = 11 ¼ " ; or write as: " x = 11.25 " .
_________________________________________________
Explanation:
_________________________________________________
(40*9) ÷ (4*8) = x ; Solve for "x" ;

(40 * 9 = 360) .

(4 * 8 = 32) .

(360) ÷ (32) = 45/4 = 11 ¼ ; or write as: 11.25 .
________________________________________________

8 0

3 years ago

Read 2 more answers

Gray is building braces for a shelf. He will attach each brace to the front edge of the 6-inch shelf and 3- inches down the wall

Llana [10]

2 inches in between each, start off on the edge go in 3 inches secound brace, than finsh on the final edge

3 0

3 years ago

What is the length of the major axis of the ellipse (x-7)^2/4+(y+3)^2/16=1

yuradex [85]

$\bf \begin{array}{llll}
\cfrac{(x-{{ h}})^2}{{{ a}}^2}+\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1\\\\ \cfrac{(x-{{ h}})^2}{{{ b}}^2}+\cfrac{(y-{{ k}})^2}{{{ a}}^2}=1
\end{array}\quad 
\begin{cases}
\textit{major axis}=a+a\\
a=\textit{the larger denominator}\\
b=\textit{smaller denominator}
\end{cases}\\\\
-----------------------------\\\\
\cfrac{(x-7)^2}{4}+\cfrac{(y+3)^2}{16}=1\implies \cfrac{(x-7)^2}{2^2}+\cfrac{(y+3)^2}{4^2}=1\quad 
\begin{cases}
a=4\\
b=2
\end{cases}$

6 0

3 years ago