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vodka [1.7K]
2 years ago
8

A programmer intended to compute (a AND b) OR c, and wrote the following code, which sometimes yields incorrect output. Why

SAT
1 answer:
atroni [7]2 years ago
3 0

A programmer intended to compute (a AND b) OR c, and wrote the following code, which sometimes yields incorrect output. The reason for this is because:

  • AND and OR are logical operators that operate on Boolean expressions to return true or false results.
  • However, | and & are bitwise operators that act on a given number's binary digits bit by bit and yield a new number after the operation.

<h3>Who is a computer programmer?</h3>

A computer programmer is a person who specializes in creating codes with which a computer is instructed to achieve a specific and expected output.

<h3>What are the other reasons for the inconsistent yield or output?</h3>

The program attempts to calculate (a AND b) OR c using the logical operators AND and OR, which will return either 1 (True) or 0 (False) depending on the inputs.

However, in the program, the programmer used the bitwise or(|) and bitwise and(&) operators: c | (a & b), which returns a new number depending on the values of a, b, and c.

As a result, it will produce the right outcome only when the logical AND - OR operation and bitwise and - or on inputs a, b, and c produce either 0 or 1. Otherwise, the outcome will be inaccurate.

As a result, the right response is that bitwise operators should be substituted by logical operators.

Learn more about programmers:
brainly.com/question/23275071
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The professor informs the class that there will be a test next week. what is the probability that a randomly selected student st
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<h3>How to calculate the probability?</h3>

In this exercise, you're required to determine the probability that students who were randomly selected studied for the test, if they pass it with a B or higher grade. Thus, we would apply Bayes's theorem.

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Therefore, we need to find P(S|B):

S|B = \frac{B|S \times S}{B|S \times S\; +\; B|S' \times S'} \\\\S|B = \frac{0.55 \times 0.6}{0.55 \times 0.6 \;+ \;0.2 \times 0.4}\\\\S|B =\frac{0.33}{0.33 + 0.08} \\\\S|B =\frac{0.33}{0.41}

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<u>Complete Question:</u>

At the beginning of the semester, a professor tells students that if they study for the tests, then there is a 55% chance they will get a B or higher on the tests. If they do not study, there is a 20% chance that they will get a B or higher on the tests. The professor knows from prior surveys that 60% of students study for the tests. The probabilities are displayed in the tree diagram.

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