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artcher [175]
2 years ago
12

Plesae help me willing to give more points

Mathematics
1 answer:
Marina86 [1]2 years ago
7 0

Answer:

a) horizontal compression with a factor of 0.5 and a horizontal reflection over the y-axis.

b) Pick one the two correct answers:

translation of 2 units right

translation of 2 units down

Step-by-step explanation:

If function f(x) is transformed into f(ax) then it is stretched or compressed horizontally.

If |a| > 1 it is compressed horizontally.

If 0 < |a| < 1, it is stretched horizontally.

If a is negative, then it is reflected over the y-axis.

a) Compare y = -2x with y = x.

The change is in that x became -2x.

Here, a = -2.

Since |-2| = 2, and 2 > 1, it has a compression of a factor of 2 horizontally.

Also, since -2 is a negative number, it is reflected over the y-axis.

Answer: horizontal compression with a factor of 0.5 and a horizontal reflection over the y-axis.

If function f(x) is transformed into f(x) + b then it is translated vertically b units. If b > 0, the translation is b units up. If b < 0, the translation is b units down.

b) y = x - 2

This can be thought of the function f(x) becoming f(x) - 2.

It is a translation of 2 units down.

Interestingly, in this case, this can also be thought of x being replaced by x - 2 which is a translation of 2 units to the right.

Answer:

There are two correct answers (use only one of the two below):

translation of 2 units right

translation of 2 units down

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First thing first. We need to see if we are working with a unit circle and find the radius.

How to tell if we are working with a unit circle?
We know x^2 + y^2 = r^2 is a circle.

We know that to find the radius we can use the following formula:
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If r^2 = \sqrt{x^2 + y^2} = 1 we are working with a unit circle.

Lets see if it = 1.
r^2 = \sqrt{4^2 + -7^2}
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r^2 = \sqrt{65}

Square both sides now
\sqrt{r^2} = \sqrt{\sqrt{65}}
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Since we squared, we have a + and a - but we disregard the - because we do not have - radii 
r = 65^{\frac{1}{4}}}
We can also say
r = \sqrt[4]{65}

Ok, since r does not equal 1, we are not working with a unit circle but we have found r, which is our radius.

Now that we know the value of r, which is r = 65^{\frac{1}{4}}}, we need to look at the identities of cos, csc and tan.


The identities:
cos \theta = \frac{x}{r}
csc \theta = \frac{1}{y}
tan \theta = \frac{y}{x}

Now that we know their identities and know the radius of our circle, we can find the exact values of cos, csc and tan.

cos \theta = \frac{x}{r} = \frac{4}{65^{\frac{1}{4}}} 
csc \theta = \frac{1}{y} = \frac{1}{-7}
tan \theta = \frac{y}{x} = \frac{-7}{4}

The exact values for cos, csc and tan given the point (4,-7) are:
cos \theta = \frac{4}{65^{\frac{1}{4}}} 
csc \theta = \frac{1}{-7}
tan \theta = \frac{-7}{4}



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