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Trava [24]
1 year ago
15

Zero and negative exponentswrite in simplest for without zero or negative exponents- 17 ⁰

Mathematics
1 answer:
Valentin [98]1 year ago
4 0
-17^0=(-17)^0=1\begin{gathered} (-2)^2\times(-2)^{-5}=(-2)^{2-5} \\ =(-2)^{-3} \\ =\frac{1}{(-2)^3} \\ =\frac{1}{-8} \end{gathered}

Thus, the final answers are 1 and -1/8.

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Evaluate the following​ integral, where R is bounded by ​, ​, and . Question content area bottom Part 1 enter your response here
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\iint_{R} y^{2} d A=\int_{x=-2}^{3} \int_{y=-x-2}^{3 x+6} y^{2} d x d y d x

\text { (taking Strip as shown). }

=\int_{-2}^{3}\left(\frac{y^{3}}{3}\right)_{-x-2}^{3 x+6} d x

=\frac{1}{3} \int_{-2}^{3}(3 x+6)^{3}-(-x-2)^{3} d x

\begin{gathered}=\frac{1}{3}[4375]=\frac{4375}{3} \\=1458.33\end{gathered}

What is integral ?

  • Calculating an integral is called integration.
  • Mathematicians utilize integrals to determine a variety of useful quantities, including areas, volumes, displacement, etc.
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So the more about integral visit.

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Step-by-step explanation:

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