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9 months ago

Zero and negative exponentswrite in simplest for without zero or negative exponents- 17 ⁰

1 answer:

4 0

$-17^0=(-17)^0=1$ $\begin{gathered} (-2)^2\times(-2)^{-5}=(-2)^{2-5} \\ =(-2)^{-3} \\ =\frac{1}{(-2)^3} \\ =\frac{1}{-8} \end{gathered}$

Thus, the final answers are 1 and -1/8.

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Plz Help

Afina-wow [57]

We are asked in the problem to determine the value of x in the equation 4x² + 2x = 7 using completing the square method. in this case,

4x² + 2x = 7
x2 + 0.5 = 1.75
(x + 0.25)^2 - 0.0625 = 1.75
(x + 0.25)^2 = 1.8125
x+0.25=1.3462
x1 =1.0963
x2 =-1.5962

3 0

2 years ago

NEED HELP ASAP!!!! PLEASE!!! Explain the answer!!

xz_007 [3.2K]

She is wrong because she did the square root of 25 multiplied by 2, she should have just done the square root of 50.

For the second part the square root of 50 is 7.07 which rounding would equal 7.1.

Hope this helps.(ﾉ◕ヮ◕)ﾉ*:･ﾟ✧

4 0

3 years ago

Find the volume of a cone with a radius of 8 cm and height 15 cm? Round to the nearest tenth. Please show work.

Nonamiya [84]

You multiply radius by 3.14 by the height if you plug it in your equation is 8×3.14×15 which equals 1005.31 which rounds to 1005, the answer is 1005! :D

4 0

2 years ago

Consider the number line with the plotted square roots.

ZanzabumX [31]

Answer: 19 Startroot and 24 endroot

Step-by-step explanation:

8 0

3 years ago

A videotape store has an average weekly gross of $1,158 with a standard deviation of $120. Let x be the store's gross during a r

statuscvo [17]

Answer:

The number of standard deviations from $1,158 to $1,360 is 1.68.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1158, \sigma = 120$

The number of standard deviations from $1,158 to $1,360 is:

This is Z when X = 1360. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1360 - 1158}{120}$

$Z = 1.68$

The number of standard deviations from $1,158 to $1,360 is 1.68.

3 0

2 years ago