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Oksanka [162]
1 year ago
14

HELPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!! in assigned photo is the question! doesnt need to be descriptive i just need the answer ple

ase, im so behind

Mathematics
2 answers:
aev [14]1 year ago
8 0

Answer: 11

Step-by-step explanation:

Since the smaller triangle is half of the larger triangle

5.5×2=11

Art [367]1 year ago
8 0

Answer:

The correct answer is 11.

Step-by-step explanation:

You might be interested in
Please help! thank you! 10+ points
jonny [76]

Answer:

A (DE = GF)

Step-by-step explanation:

In a isosceles trapezoid, one pair of segments are parallel, and another pair are equivalent in length.

The only choice that fits this criteria is A, where DE equals GF.

7 0
3 years ago
Read 2 more answers
Write 0.0007654 * 10^0 in scientific notation, then state the order of magnitude for it.
Bas_tet [7]

remember that to put a number in scientific notation is necessary to have the first digit of the number different to 0, so

0.0007654\cdot10^0=7.654\cdot10^{-4}

to calculate the order of magnitude, if the number is greater than 3.16, we assume it as a 10, so in this case as 7.654 > 3.16 we get that the order is

10\cdot10^{-4}=10^{-3}

So the order is 10^-3

5 0
1 year ago
I have no idea what to do pls help ​
kati45 [8]

Answer:

101 = first number

115= second number

101+115=116

101 and 115

yes they are odd because you can not add two nubers to make 101 or 115

yes. they do add up to 116.

Step-by-step explanation: hope this helped

7 0
3 years ago
Find the volume of the solid under the plane 5x + 9y − z = 0 and above the region bounded by y = x and y = x4.
svp [43]
<span>For the plane, we have z = 5x + 9y

For the region, we first find its boundary curves' points of intersection.
x = x^4 ==> x = 0, 1.

Since x > x^4 for y in [0, 1],

The volume of the solid equals

\int\limits^1_0 { \int\limits_{x^4}^x {(5x+9y)} \, dy } \, dx = \int\limits^1_0 {\left[5xy+ \frac{9}{2} y^2\right]_{x^4}^{x}} \, dx  \\  \\ =\int\limits^1_0 {\left[\left(5x(x)+ \frac{9}{2} (x)^2\right)-\left(5x(x^4)+ \frac{9}{2} (x^4)^2\right)\right]} \, dx  \\  \\ =\int\limits^1_0 {\left(5x^2+ \frac{9}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx =\int\limits^1_0 {\left( \frac{19}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx \\  \\ =\left[ \frac{19}{6} x^3- \frac{5}{6} x^6- \frac{1}{2} x^9\right]^1_0

=\frac{19}{6} - \frac{5}{6} - \frac{1}{2} =\bold{ \frac{11}{6} \ cubic \ units}</span>
8 0
3 years ago
Please help!!!!!!!!!!
Sergeu [11.5K]
1, 3, and 5 would be my best guesses but I’m not 100 percent sure
7 0
3 years ago
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