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2 years ago

Complete the equations to solve 1{,}860 \div61,860÷61, comma, 860, divided by, 6.

Mathematics

1 answer:

coldgirl [10]2 years ago

7 0

The division of the figure based on the information is 14.09.

<h3>How to illustrate the information?</h3>

It should be noted that the question is simply to divide 860 by 61.

The division based on the information will be illustrated thus:

= 860 ÷ 61

= 14.09

In conclusion, the correct option is 14.09.

Learn more about division on:

brainly.com/question/1622425

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

lozanna [386]

<h3>The length of legs of isosceles right triangle is 8.5 cm</h3>

<em><u>Solution:</u></em>

Given is a isosceles triangle

hypotenuse = 12 cm

In an isosceles right triangle, the legs have equal lengths

Let these sides be each "a" cm

By pythogoras theorem,

$(Hypotenuse)^2 = (leg)^2 + (leg)^2\\\\12^2 = a^2+a^2\\\\2a^2 = 144\\\\a^2 = 72\\\\Take\ square\ root\ on\ both\ sides\\\\a = \sqrt{72}\\\\a = 8.49 \approx 8.5$

Thus the length of leg of isosceles right triangle is 8.5 cm

6 0

3 years ago

1 Find the area of the shaded region in the figure below. Show your work or explain your steps below.

lozanna [386]

Answer:

66 cm²

Step-by-step explanation:

<u>Shaded region (blue) is the difference of areas of big and small triangles</u>

A = 1/2(16*12 - 10*6) = 66 cm²

<em>The answer options are incorrect</em>

3 0

3 years ago

Read 2 more answers

The rule Rx-axis o is applied to the point (-3,-2). Where is the image in the coordinate

Nastasia [14]

Answer:

$Image = (-3,2)$

Step-by-step explanation:

Given

$Point = (-3,-2)$

Transformation = Rx-axis

Required

Determine the image

When rule Rx-axis is applied to a point (x,y),

The new coordinate point is (x,-y)

<em>In other words, the y coordinate is negated</em>

So, when rule Rx-axis is applied to

$Point = (-3,-2)$

The image of the point is

$Image = (-3,-(-2))$

$Image = (-3,2)$

4 0

3 years ago

(sin Θ − cos Θ)^2 − (sin Θ + cos Θ)^2

Andru [333]

More generally, we have

$(a-b)^2-(a+b)^2=(a^2-2ab+b^2)-(a^2+2ab+b^2)=-4ab$

so that

$(\sin\theta-\cos\theta)^2-(\sin\theta+\cos\theta)^2=-4\sin\theta\cos\theta=-2\sin2\theta$

7 0

3 years ago

Need help bad !!!!!!!!!!!!

Nonamiya [84]

There are 2 order pairs there (6,-4),(-2,4)
find the midpoint using the formula

(x1+x2)/2 , (y1+y2)/2
x=6 and -2
y=-4 and 4

(6+2)/2 , (-4+4)/2
8/2 ,0/2
the midpoint is (4,0) A

4 0

4 years ago

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