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Dennis_Churaev [7]

1 year ago

11

There were 50,000 bacteria in a petri dish yesterday at noon, and 40,000 bacteria at noon today. if the trend continues, on what

day at noon can you expect to find less than 5,000 bacteria?

1 answer:

Arlecino [84]1 year ago

7 0

Answer:

900

Step-by-step explanation:

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11111nata11111 [884]

Here you go enjoy

Have a good rest of your night

5 0

2 years ago

I have to find the value of x please help me will give brainliest to correct answer

Semenov [28]

Answer:

C. x = 5

Step-by-step explanation:

48 = 7x + 13

-13 -13

35 = 7x

5 = x

7 0

2 years ago

The picture shows the Alamillo bridge in Seville, Spain. In the picture m<1=58 and m<2=24. Find the measure of the supplem

Anna11 [10]

Answer:

Supplement of <1 = 122°

Supplement of <2 = 156°

Step-by-step explanation:

Two pairs of angles are said to be supplementary, if their measures in degrees add up to give us 180°. A supplement of am angle is simply 180° - the measure of that angle.

Given that meadure of angle 1 = 58°, the supplement of angle 1 = 180° - 58° = 122°

Also, if the measure of angle 2 = 24°, the supplement of angle 2 = 180° - 24° = 156°.

Thus:

Supplement of <1 = 122°

Supplement of <2 = 156°

6 0

3 years ago

Can you help me with this? thanks made it 20 points!

liraira [26]

I agree with Roaltyjess<span />

8 0

3 years ago

Use spherical coordinates. evaluate (9 − x2 − y2) dv, where h is the solid hemisphere x2 + y2 + z2 ≤ 4, z ≥ 0.

avanturin [10]

In spherical coordinates, we have

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}$

which gives volume element

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

and so the triple integral is given by

$\displaystyle\iiint_H(9-x^2-y^2)\,\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9-\rho^2\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$
$=\displaystyle2\pi\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9\rho^2\sin\varphi-\rho^4\sin^3\varphi)\,\mathrm d\rho\,\mathrm d\varphi$
$=\dfrac{592\pi}{15}$

4 0

3 years ago