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Julli [10]
3 years ago
5

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 20 m/s. The ball's height h (in meters) a

fter t seconds is given by h=2+20t-5t^2. find all values of t for which the ball's height is 12 meters. Round your answers to the nearest tenth of a second.
Mathematics
1 answer:
vovangra [49]3 years ago
6 0
So 12 = 2 + 20t -5t^2

5t^2 -20t + 10=0

t^2 -4t + 2 = 0

Use quadratic formula to solve
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Answer:

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Step-by-step explanation:

<u>Step 1:  Make common denominators</u>

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<em>15/21 * 1/1 = 15/21</em>

<em>5/7 * 3/3 = 15/21</em>

<em />

<u>Step 2:  Subtract the numbers</u>

15/21 - 5/7 is same as 15/21 - 15/21

15/21 - 15/21

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Answer:  0

3 0
4 years ago
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inysia [295]
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3 years ago
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monitta

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Step-by-step explanation:

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