Question

Help me w this pls thanks

Answer 1

Answer:

Perimeter: 4+$\pi$ mm

Area: $\pi$ mm^2

Step-by-step explanation:

Perimeter:

90/360 * 4$\pi$ +2 + 2 = 4+ $\pi$

Area:

90/360 * 4$\pi$ = $\pi$

Answer 2

Answer: 7.14 mm and 3.14 mm²

Step-by-step explanation:

The perimeter of a figure is the total length on the outside of the figure. A regular circle has a perimeter of $2\pi r$, where r is the radius and $\pi$ is an irrational constant, approximately 3.14.

Due to the right angle, we know that this is a quarter circle, as it is a quarter of 360°, or a full circle. Hence, the curved portion of the quarter circle is $\frac{1}{4}* 2\pi r$ or $\frac{1}{2} \pi r$. The radius is 2 mm, so this value is

$\frac{1}{2} \pi*2=\pi$

However, this isn't the total perimeter, as there are straight edges in the figure too. Both edges are radii of the whole circle, so both would be 2mm. Their total is

$2+2=4$

By adding $\pi$ to 4 we get $\pi +4$ or 7.14 mm.

The  area is the total space enclosed by a figure. The total area of a whole circle is $\pi r^2$, where r is still the radius. Since this is a quarter circle, it would take up a quarter of the area, or $\frac{1}{4} \pi r^2$. We can plug in 2 for r and solve to get the area.

$\frac{1}{4}\pi*2^2\\\frac{1}{4}\pi*4\\\pi$

Hence, the area is $\pi$, or around 3.14 mm².