Answer:
n is a positive integer and here 90, 91, 92, 93, 94 and 95 is 9⁰ = 1
9¹ = 9
9² = 81
9³ = 729
9⁴ = 6561
9⁵ = 59049
so mathematical induction is prove given below.
Step-by-step explanation:
9⁰ = 1
9¹ = 9
9² = 81
9³ = 729
9⁴ = 6561
9⁵ = 59049
lets us consider by P (n) for the base case n = 0 then 9⁰ = 1 So P (1) is true
k ≥ 1so consider all integers
1≤l≤ k
There is a need to prove P (k+1)
if k is odd
=
.9.
is 9 so
= 9 +10m
then
= 9 ( 9 + 10m)
=81 + 10 (9m)
so digit is 1 and k +1 is even
I’m not sure if it’s correct but I think you have to find the slope in order to get your answer
Using the slip and slide method:
2x^2+5x-12
x^2+5x-24
(x+8)(x-3)
(x+8/2)(x-3/2)
(x+4)(2x-3)
Final answer: (2x-3)(x+4)
Answer:
here's the solution :-
Step-by-step explanation:
i hope it helped...
You mix the letters m,a,t,h,e,m,a,t,i,c,a and l thoroughly without looking you draw one letter probability p(A) . write the prob
erastovalidia [21]
There are 12 total letters, of which 3 are A's.
This means you have a
probability of randomly selecting an A.
