Question

I need help with my work

Answer 1

(In c) * 1/c = 0.0604 is the change in the function.

According to the statement

y = (In x)^2 on interval [1,4]

By mean value theorem

we use this formula to find a change f '(c)= [f(b) - f(a)] / (b - a)

Let it f(y) = (In x)^2

Now, f(4) = (In 4)^2

f(4) = (0.602)^2

f(4) = 0.3624

and

f(1) = (In 1)^2

f(1) = (0)^2

f(1) = 0

Now, f'(c) = 2 (In c) * 1/c

Substitute all these values in a formula

2 (In c) * 1/c = 0.3624 - 0 / 4 - 1

2 (In c) * 1/c = 0.3624/3

2 (In c) * 1/c = 0.1208

(In c) * 1/c = 0.0604

So, (In c) * 1/c = 0.0604 is the change in the function.

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