(In c) * 1/c = 0.0604 is the change in the function.
According to the statement
y = (In x)^2 on interval [1,4]
By mean value theorem
we use this formula to find a change f '(c)= [f(b) - f(a)] / (b - a)
Let it f(y) = (In x)^2
Now, f(4) = (In 4)^2
f(4) = (0.602)^2
f(4) = 0.3624
and
f(1) = (In 1)^2
f(1) = (0)^2
f(1) = 0
Now, f'(c) = 2 (In c) * 1/c
Substitute all these values in a formula
2 (In c) * 1/c = 0.3624 - 0 / 4 - 1
2 (In c) * 1/c = 0.3624/3
2 (In c) * 1/c = 0.1208
(In c) * 1/c = 0.0604
So, (In c) * 1/c = 0.0604 is the change in the function.
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