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2 years ago

Hellp please!!!!!!!

Mathematics

1 answer:

slega [8]2 years ago

5 0

4. z = 75

6. t = 4/3 or t = 1.3 repeating

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Example of different types of function.

VLD [36.1K]

there are many types of functions this includes linear function (straight line graph) eg y=3x+2 , quadratic function (u shaped curve) eg y=x², logarithmic function, exponential function and etc

3 0

2 years ago

The top of a mountain is 2,450 feet above sea level a shipwreck was discover 310 feet below sea level what is the distance betwe

arlik [135]

Answer:

$d=2,760\ ft$

Step-by-step explanation:

Let

x ----> the height of the top of a mountain above sea level

y ----> the deep of a shipwreck below the sea level

we know that

The sea level represent the height equal to zero

In this problem we have

$x=2,450\ ft$ ---> is positive because is above sea level

$y=-310\ ft$ ---> is negative because is below sea level

To find out the distance between the mountain top and the ship wreck, determine the absolute value of the difference between the two values

$d=\left|x-y\right|$

substitute the values

$d=\left|2,450-(-310)\right|$

$d=\left|2,450+310\right|$

$d=\left|2,760\right|$

$d=2,760\ ft$

5 0

2 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

2 years ago

Butterfly: wingspan 20 cm silk butterfly: wingspan 4 cm

MA_775_DIABLO [31]

Answer:

(silk butterfly numerator )(butterfly denominator) 4cm/20cm = 1cm/5cm

6 0

3 years ago

Is this right? I don't know it I'm correct or not.

faust18 [17]

Answer:

you are correct!!

3 0

2 years ago

Hellp please!!!!!!!​

Hellp please!!!!!!!