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2 years ago

Which choice is equivalent to the quotient shown here for acceptable

Mathematics

1 answer:

evablogger [386]2 years ago

3 0

The equivalent to the quotient shown in the task content for acceptable values of x is; √(5/(x-1)).

<h3>What is the equivalent of the quotient?</h3>

It follows from the task content that the expression given is; √(25(x-1)) ÷ √(5(x-1)²).

It therefore follows from the the laws of indices that the evaluation is thus;

= √{(25/5) ×(x-1)/(x-1)²}.

Ultimately, upon evaluation we have;

= √(5/(x-1))

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A carnival charges S5 for admission plus $2 per ride. Write an expression for the cost of admission plus r rides. How many rides

Airida [17]

Answer : 5 rides

Explanation

15=5+2r
-5 -5
10=2r
/2 /2
5=r

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4 years ago

Two sides of a right triangle have lengths of 4 centimeters and 7 centimeters. The third side is NOT the hypotenuse. How long is

andrezito [222]

Answer:

The third side is 5.7 centimeters.

Step-by-step explanation:

The hypothenuse is the largest side of a right triangle. So in this question, we know that the hypothenuse is 7.

One of the sides is 4, and the other is x.

Applying Pythagoras' Theorem:

$x^{2} + 4^{2} = 7^{2}$

$x^{2} = 49 - 16$

$x^{2} = 33$

$x = \pm \sqrt{33}$

Since it is a length measure, we only take the positive value

$x = 5.7$

The third side is 5.7 centimeters.

6 0

3 years ago

What type of triangle measures 6 inches, 8 inches, and 10 inches with on 90 degree angle?

bearhunter [10]

I think it would be a right triangle

7 0

3 years ago

Read 2 more answers

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0

4 years ago

Volunteers at Sam's school use some of the student council's savings for a special project. They buy 3 backpacks for $7 each and

nydimaria [60]

Answer:

Sam's student council spent $39 on backpacks + paper and pens.

Step-by-step explanation:

They bought 3 backpacks for $7 each. 3 x 7 = $21.

They also filled those backpacks with paper and pens costing $6 each. 3 backpacks x $6 = $18.

Now, add the two prices.

18 + 21 = 39

<em>hope this helps :)</em>

3 0

3 years ago

Read 2 more answers