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OleMash [197]
1 year ago
12

Which graph best represents the solution to the system of equations shown below? y = -2x + 14 y = 2x + 2 A coordinate grid is sh

own from negative 10 to positive 10 on the x axis and also on the y axis. Two lines are shown intersecting on the ordered pair 3, 8. A coordinate grid is shown from negative 10 to positive 10 on the x axis and also on the y axis. Two lines are shown intersecting on ordered pair 8, 3. A coordinate grid is shown from negative 10 to positive 10 on the x axis and also on the y axis. Two lines are shown intersecting on ordered pair negative 8, negative 3. A coordinate grid is shown from negative 10 to positive 10 on the x axis and also on the y axis. Two lines are shown intersecting on ordered pair negative 3, 8.
Mathematics
1 answer:
slega [8]1 year ago
5 0

The graph whuch best represents the solution to the system of equations is; A coordinate grid is shown from negative 10 to positive 10 on the x axis and also on the y axis. Two lines are shown intersecting on the ordered pair 3, 8.

<h3>What is the graphical solution of the system big equations?</h3>

As an alternative, solving the system of equations algebraically, we have;

-2x +14 = 2x +2

x = 3 and by substitution;

y = 8.

On this note, the point (3,8) is a solution of the graph and hence, the answer choice with two lines intersecting at (3,8) is correct.

Read more on graphical solution of a system of equations;

brainly.com/question/14323743

#SPJ1

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What decimal number is about equal to 1/6?​
baherus [9]

Answer:

Step-by-step explanation: 0.16

6 0
2 years ago
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Researchers at the Centers for Disease Control and Prevention have been studying the decay pattern of a new virus with a decay r
koban [17]

The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

Step-by-step explanation:

The given is,

                     A new virus with a decay rate of 19% per hour  

                    They start with 300 viruses

Step:1

                  Formula to calculate the viruses at decay rate,

                                                  y = A(1-r)^{t}............................(1)

                 Where, y - No of viruses after given time

                             A - Viruses at initial stage

                              r - Decay rate

                              t - No. of hours

                 From the given,

                              A = 300

                               r = 19% per hour

                               t = 7 hours

                Equation (1) becomes,

                                            y = 300(1-0.19)^{7}

                                               = 300(0.81)^{7}

                                               = 300(0.228767)

                                               = 68.63

               Viruses of 7 hours ≅ 69 viruses

                                                     ( or )

Step:1

        For 1st hour,

          = (No.of viruses in hour) - (No,of viruses in last hour × Decay rate )

              = (300)-(300 × 0.19)

              = 300 - 57

              = 243

       For 2nd hour,

              = (243)-(243 × 0.19)

              = 243 - 46.17

              = 196.83

      For 3rd hour,

              = (196.83)-(196.83 × 0.19)

              = 196.83 - 37.39

              = 159.4323

       For 4th hour,

              = (159.4323)-(159.4323 × 0.19)

              = 159.4323 - 30.2921

              = 129.1402

      For 5th hour,

              = (129.1402)-(129.1402 × 0.19)

              = 129.1402 - 24.5366

              = 104.6035

     For 6th hour,

              = ( 104.6035)-( 104.6035 × 0.19)

              =  104.6035 - 19.8747

              = 84.7288

     For 7th hour,

              = (84.7288)-(84.7288 × 0.19)

              =  84.7288 - 16.0984

              = 68.63 viruses

Result:

          The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

7 0
3 years ago
(THIS IS A TEST I NEED HELP)
Leya [2.2K]

Answer:

Option (B)

Step-by-step explanation:

Length of PR = 4

RS = 4

QS = 4

For the length of PT,

PT² = RT² + PR² [Since, PT is the diagonal of rectangle PRT]

PT² = QS² + PR² [Since, RT ≅ QS]

PT² = 4² + 7²

PT² = 16 + 49

PT² = 65

Now for the length of PQ,

PQ² = QT² + PT²

PQ² = RS² + PT² [Since, QT ≅ RS]

PQ² = 4² + 65

PQ² = 16 + 65

PQ = √81

PQ = 9

Therefore, length of diagonal PQ is 9 units.

Option (B) will be the answer.

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Answer:

4/5 is the slope.

6 0
3 years ago
Find the volume of the solid figure shown below. The area of the base is 40 square inches and the height of the figure is 7 inch
Marrrta [24]

Answer:

\displaystyle V _{ \text{cuboid}} =280  {in}^{3}

Step-by-step explanation:

we are given the base area and the height of a solid figure

since the base area is not perfect square

we assure the solid figure to be a cuboid

remember that,

\displaystyle V _{ \text{cuboid}} = l\times w \times h

we are given l×w is 40 and h is 7

so substitute

\displaystyle V _{ \text{cuboid}} =40 \times 7

simplify multiplication:

\displaystyle V _{ \text{cuboid}} =280

hence,

the volume of the figure is 280 in³

4 0
3 years ago
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