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mylen [45]
2 years ago
15

Write out the sum. Do not evaluate.∑∑k=1 (k^2-5k-3)

" id="TexFormula1" title="4\\E(K^2-5k-3)\\k=1" alt="4\\E(K^2-5k-3)\\k=1" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
VARVARA [1.3K]2 years ago
8 0

Series are sum of a given sequence.. The sum of the given expression is -33

<h3>Sequence and series</h3>

Series are sum of a given sequence. According to the given expression

∑∑k=1 (k^2-5k-3)

Taking the sum from k = 1 to k = 4

Sum = (1-5-3) + (4-10-3) +(9-15-3)+(15-20-3)

Sum = (-7) + (-9) + (-9) + (-8)

Sum = -33

Hence the sum of the given expression is -33

Learn more on sum notation here: brainly.com/question/542712

#SPJ1

You might be interested in
If the width of a rectangle is 3 and the perimeter is 20 what is the missing side length
I am Lyosha [343]
The formula to find the perimeter of a rectangle is:

P = 2(l + w)

plug in your known values to solve for the unknown

20 = 2(l + 3)
20 = 2l + 6
14 = 2l
14/2 = l
7 = l or l = 7

you can check this by plugging your l value into the equation

P = 2(l + w)
20 = 2(7 + 3)
20 = 2(10)
20 = 20

hope this helps :)



8 0
4 years ago
Is the distribution of all values of the statistic when all possible samples of the same size n are taken from the same populati
olganol [36]

The distribution of the values obtained from a simple random sample of size n from the same population is incorrect.

<h3>What is sampling distribution?</h3>

The sampling distribution of a statistic of size n is the distribution of the values obtained from a simple random sample of size n from the same population.

The sampling distribution is the process of getting a sample through simple random techniques from the sample population.

So, it is incorrect that the distribution of all values of the statistic when all possible samples of the same size n are taken from the same population.

Learn more about sampling distribution  here:

brainly.com/question/3663642

#SPJ1

8 0
2 years ago
Put 5x + 5y = -3,500 into a slope-intercept form
GREYUIT [131]
Slope intercept form is y=mx+b
y=-x+700
4 0
3 years ago
Read 2 more answers
Verify that y1(t) = 1 and y2(t) = t ^1/2 are solutions of the differential equation:
Papessa [141]

Answer: it is verified that:

* y1 and y2 are solutions to the differential equation,

* c1 + c2t^(1/2) is not a solution.

Step-by-step explanation:

Given the differential equation

yy'' + (y')² = 0

To verify that y1 solutions to the DE, differentiate y1 twice and substitute the values of y1'' for y'', y1' for y', and y1 for y into the DE. If it is equal to 0, then it is a solution. Do this for y2 as well.

Now,

y1 = 1

y1' = 0

y'' = 0

So,

y1y1'' + (y1')² = (1)(0) + (0)² = 0

Hence, y1 is a solution.

y2 = t^(1/2)

y2' = (1/2)t^(-1/2)

y2'' = (-1/4)t^(-3/2)

So,

y2y2'' + (y2')² = t^(1/2)×(-1/4)t^(-3/2) + [(1/2)t^(-1/2)]² = (-1/4)t^(-1) + (1/4)t^(-1) = 0

Hence, y2 is a solution.

Now, for some nonzero constants, c1 and c2, suppose c1 + c2t^(1/2) is a solution, then y = c1 + c2t^(1/2) satisfies the differential equation.

Let us differentiate this twice, and verify if it satisfies the differential equation.

y = c1 + c2t^(1/2)

y' = (1/2)c2t^(-1/2)

y'' = (-1/4)c2t(-3/2)

yy'' + (y')² = [c1 + c2t^(1/2)][(-1/4)c2t(-3/2)] + [(1/2)c2t^(-1/2)]²

= (-1/4)c1c2t(-3/2) + (-1/4)(c2)²t(-3/2) + (1/4)(c2)²t^(-1)

= (-1/4)c1c2t(-3/2)

≠ 0

This clearly doesn't satisfy the differential equation, hence, it is not a solution.

6 0
3 years ago
Plzz show workings while giving the answer​
sukhopar [10]

Answer:

\huge\boxed{\sf 4\ minutes\ 1.5\ seconds}

Step-by-step explanation:

3 minutes 59.1 seconds = (3*60) + 59.1 seconds = 180 + 59.1 seconds

=> 239.1 seconds

\rule[225]{225}{2}

4 minutes 3.8 seconds = (4*60) + 3.8 seconds = 240 + 3.8 seconds

=> 243.8 seconds

\rule[225]{225}{2}

4 minutes 1.6 seconds = (4*60) + 1.6 seconds = 240 + 1.6 seconds

=> 241.6 seconds

\rule[225]{225}{2}

Mean = Sum of data / No. of Data

Mean = 239.1 + 243.8 + 241.6 / 3

Mean = 724.5 / 3

Mean = 241.5 seconds

<u>In Minutes and Seconds:</u>

= 241.5 / 60 = 4.025 minutes

= 4 minutes + 0.025 minutes

= 4 minutes + (0.025 * 60) seconds

= 4 minutes 1.5 seconds

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>

8 0
3 years ago
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