Question

Solve for unknown in 2x^3+6x^2-20x=0​

Answer 1

The solution of x is x = 0, x =2 and x = -5

How to solve for the unknown?

The equation is given as:

2x^3+6x^2-20x=0​

Factor out x

x(2x^2+6x-20)=0​

Split the equation

x = 0 or 2x^2+6x - 20=0​

Solve for x in 2x^2+6x - 20=0​

Expand the equation

2x^2 + 10x - 4x - 20 = 0

Factorize the equation

(2x - 4)(x +5) = 0

Split the equation

2x - 4 = 0 and x + 5 = 0

Solve for x

x =2 and x = -5

Hence, the solution of x is x = 0, x =2 and x = -5

Read more about equations at:

brainly.com/question/13712241

#SPJ1