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aleksklad [387]
2 years ago
11

Solve for unknown in 2x^3+6x^2-20x=0​

Mathematics
1 answer:
Licemer1 [7]2 years ago
3 0

The solution of x is x = 0, x =2 and x = -5

<h3>How to solve for the unknown?</h3>

The equation is given as:

2x^3+6x^2-20x=0​

Factor out x

x(2x^2+6x-20)=0​

Split the equation

x = 0 or 2x^2+6x - 20=0​

Solve for x in 2x^2+6x - 20=0​

Expand the equation

2x^2 + 10x - 4x - 20 = 0

Factorize the equation

(2x - 4)(x +5) = 0

Split the equation

2x - 4 = 0 and x + 5 = 0

Solve for x

x =2 and x = -5

Hence, the solution of x is x = 0, x =2 and x = -5

Read more about equations at:

brainly.com/question/13712241

#SPJ1

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Answer:

We conclude that majority of the citizens does not feel the country could develop a way to protect itself from atomic bombs.

Step-by-step explanation:

We are given that an organization asked 1403 randomly sampled American​ citizens, "Do you think we can develop a way to protect ourselves from atomic bombs in case others tried to use them against​ us?" with 737 responding yes.

We have to conduct a test to determine that a majority of the citizens feel the country could develop a way to protect itself from atomic bombs in 1945.

<u><em>Let p = percentage of citizens feel the country could develop a way to protect itself from atomic bombs in 1945.</em></u>

SO, Null Hypothesis, H_0 : p \leq 50%   {means that majority of the citizens does not feel the country could develop a way to protect itself from atomic bombs}

Alternate Hypothesis, H_A : p > 50%   {means that majority of the citizens feel the country could develop a way to protect itself from atomic bombs}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = proportion of citizens responding yes in a sample of 1403 citizens =  \frac{737}{1403}  

           n = sample of citizens = 1403

So, <u><em>test statistics</em></u>  =  \frac{\frac{737}{1403} -0.50}{{\sqrt{\frac{\frac{737}{1403}(1-\frac{737}{1403})}{1403} } } } }

                               =  1.898

The value of the test statistics is 1.898.

<em>Now at 1% significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is less than the critical value of z as 1.898 < 2.3263, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that majority of the citizens does not feel the country could develop a way to protect itself from atomic bombs.

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Answer:

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Step-by-step explanation:

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