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aleksklad [387]
2 years ago
11

Solve for unknown in 2x^3+6x^2-20x=0​

Mathematics
1 answer:
Licemer1 [7]2 years ago
3 0

The solution of x is x = 0, x =2 and x = -5

<h3>How to solve for the unknown?</h3>

The equation is given as:

2x^3+6x^2-20x=0​

Factor out x

x(2x^2+6x-20)=0​

Split the equation

x = 0 or 2x^2+6x - 20=0​

Solve for x in 2x^2+6x - 20=0​

Expand the equation

2x^2 + 10x - 4x - 20 = 0

Factorize the equation

(2x - 4)(x +5) = 0

Split the equation

2x - 4 = 0 and x + 5 = 0

Solve for x

x =2 and x = -5

Hence, the solution of x is x = 0, x =2 and x = -5

Read more about equations at:

brainly.com/question/13712241

#SPJ1

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when you use a mirror and you look at the shape on both sides then you will see the -x which is basically on the same side but just a minus instead. Soo let's say you have to graph a coordinate of (2,4) y=2 and x=4 si you have to graph the normal plots and when you put it in the opposite sides the thing you only did was you just made a reflection of the shape just negative instead. hope you understand what I'm saying.

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Can someone help me find the midpoint?
ioda

Answer:

(6,-2.5)

Step-by-step explanation:

The formula for the midpoint between two points is:

(\frac{x_{1} + x_{2}}{2},\frac{y_{1}+y_{2}}{2})

Now we substitute

We have than (9, -1) is (x_{1}, y_{1}) and (3, - 4) is (x_{2}, y_{2})

So:

(\frac{(9) + (3)}{2},\frac{(-1)+(-4)}{2})\\\\(-1) + (-4) = -5\\9 + 3 = 12\\

So, we have:

(\frac{12}{2}, \frac{-5}{2})\\\\12 / 2 = 6\\-5 / 2 = -2.5\\\\(6, -2.5)

<h2>(6,-2.5)</h2><h2 />

I can do a graphic explanation if you want.

6 0
3 years ago
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