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Dennis_Churaev [7]
2 years ago
6

A rectangular floor measures $a$ feet by $b$ feet, where $a$ and $b$ are positive integers with $b > a$. An artist paints a r

ectangle on the floor with the sides of the rectangle parallel to the sides of the floor. The unpainted part of the floor forms a border of width 1 foot around the painted rectangle and occupies half the area of the entire floor. How many possibilities are there for the ordered pair $(a,b)$?
Business
1 answer:
DENIUS [597]2 years ago
8 0

The number of possibilities that are there for the ordered pair is 2.

<h3>Calculation and Parameters
</h3>

Because the unpainted part of the floor covers 1/2 of the area, then the painted rectangle covers 1/2 of the area as well.

Given that the border width is 1 foot, the dimensions of the rectangle are a-2 by b-2.

Making an equation:

ab= 2((a-2)(b-2))

ab= 2ab-4a-4b+8

ab-4a-4b+8=0

If we apply Simon's Favorite Factoring Trick,

ab-4a-4b+16= 8

(a-4)(b-4)= 8

Since b > a, then we have the possibilities

(a-4) = 1 and (b-4) = 8, or (a-4) = 2 and (b-4) = 4.

(5, 12) or (6,8) which gives us 2 possibilities.

Read more about possibilities here:

brainly.com/question/25870256

#SPJ1

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1. 9.4. For process scheduling, does a low-priority value represent a low priority or a high priority?
sergeinik [125]

Answer:

Priority programming is a process programming method based on priority. In this technique, the developer chooses the tasks to work according to priority, which is different from other types of programming, for example, a simple round-robin.

On UNIX and many other systems, higher priority values represent lower priority processes. Some of the systems, such as Windows, use the opposite convention: a higher number means a higher priority

Explanation:

Priorities can be dynamic or static. Static priorities are assigned during creation, while dynamic priorities are assigned according to the behavior of the processes while they are in the system. To illustrate, the planner could favor intensive input / output (I / O) tasks, allowing expensive requests to be issued as soon as possible.

Priorities can be defined internally or externally. Internally defined priorities make use of a measurable amount to calculate the priority of a given process. On the contrary, external priorities are defined using criteria beyond the operating system (OS), which may include the importance of the process, the type and sum of the resources used for the use of the computer, user preferences , trade and other factors such as politics etc.

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An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

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Answer:

Employees attitude to customers (Customer Relationship) and the quality of the food are the two most important trends that would bring about an increase in sales.

Explanation:

The first instrument of effective sales is an establish relationship. If a customers visits a restaurant to buy food and does not feel welcomed, the tendency to return back another time is very slim. Hnece, taking the scenerio in questions,the employees do not have the right attitude for keepiing their customers loyal to their product irrespective of whether the product is good or bad.

On the other hand, the reason for visiting a restaurant is to eat good food and not bad. So, when the quality of food cooked by the restaurant does not meet the taste and quality expected by the customer, the possibility of having such customer come around again is low. This invariably implies loosing the customer and the chain of connections such customer would have brought to the restaurant.

In summary, having the right employees with good customer relationship and chefs with good food recipes and quality is likely to result in the restaurant experiencing an increase in sales

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